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a) Ta có \(0,625^{200}=\left(\dfrac{5}{8}\right)^{200}\) và \(0,5^{1000}=\left(\dfrac{1}{2}\right)^{1000}=\left(\dfrac{1}{2}\right)^{5.200}\) \(=\left[\left(\dfrac{1}{2}\right)^5\right]^{200}\) \(=\left(\dfrac{1}{32}\right)^{200}\). Mà hiển nhiên \(\left(\dfrac{5}{8}\right)^{200}>\left(\dfrac{1}{32}\right)^{200}\) nên suy ra \(0,625^{200}>0,5^{1000}\)
b) Ta thấy \(\left(-32\right)^{27}< 0\) trong khi \(\left(-27\right)^{32}>0\) nên đương nhiên \(\left(-32\right)^{27}< \left(-27\right)^{32}\)
c) Ta thấy \(-\dfrac{3}{2}>-2\) nên \(\left(-\dfrac{3}{2}\right)^5>\left(-2\right)^5\)
Ta có:a)\(^{3^{600}}\)=\(^{\left(3^3\right)^{200}}\)=\(^{27^{200}}\) \(^{4^{400}}\)=\(^{\left(4^2\right)^{200}}\)=\(^{16^{200}}\)
vì 27^200>16^200 => 3^600>4^400
b) \(^{4^{32}=4^{2.16}=16^{16}}\) vì 16^16>16^15 => 4^32>16^15
\(3^{600}=3^{200.3}=\left(3^3\right)^{200}=9^{200}^{_{\left(1\right)}}\)
\(4^{400}=\left(2^2\right)^{400}=2^{800}=2^{200.4}=\left(2^4\right)^{200}=16^{200}_{\left(2\right)}.\)
\(\left(1\right),\left(2\right)\Rightarrow4^{400}>3^{600}\)
\(4^{32}=\left(2^2\right)^{32}=2^{64}_{\left(1\right)}\)
\(16^{15}=\left(2^4\right)^{15}=2^{60}_{\left(2\right)}\)
\(\left(1\right),\left(2\right)\Rightarrow4^{32}>16^{15}\)
4^32=16^16
mà 16^16>16^15
suy ra 4^32>16^15
GTNN của A =2 khi x =3
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1). 4^x:16^4=32^2
=>2^2x:(2^4)^4=(2^5)^2
=>2^2x:2^16=2^10
=>2^2x=2^10.2^16
=>2^2x=2^26
=>2x=26
=>x=26:2=13
2)Ta có:
+)3^1000=(3^4)^250=81^250
+)5^750=(5^3)^250=125^250
Vì :81^250<125^250 nên 3^1000<5^750