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Ta có /3x-1/=/2x+1/.Ta xét 2 th
TH1 3x-1=-(2x+1) Th2 3x-1=2x+1 Vậy x thuộc{0;2}
3x-1= -2x-1 3x-1-2x=1
3x-1=-2x+(-1) 3x-2x-1=1
3x-1-(-2x)=-1 x-1=1
3x-1+2x=-1 x=1+1
(3x+2x)-1=-1 x=2
x.5 =-1+1
x.5 =0
x= 0:5
x=0
xy-3x+y=19
<=>x(y-3)+(y-3)=19
<=>(x+1)(y-3)=19
=>
x+1 | 1 | 19 | -1 | -19 |
y-3 | 19 | 1 | -19 | -1 |
x | 0 | 18 | -2 | -20 |
y | 22 | 4 | -16 | 2 |
\(\frac{x-2}{2}-\frac{1+x}{3}=\frac{4-3x}{4}-1\)
\(\Leftrightarrow\frac{3\left(x-2\right)-2\left(1+x\right)}{6}=\frac{4-3x-4}{4}\)
\(\Leftrightarrow\frac{3x-6-2-2x}{6}=-\frac{3x}{4}\)
\(\Leftrightarrow\frac{x-8}{6}=-\frac{3x}{4}\)
\(\Leftrightarrow4x-32=-18x\)
\(\Rightarrow x=\frac{16}{11}\)
5.(x - 1) = 3x + 7
=> 5x - 5 = 3x + 7
=> 5x - 3x = 7 + 5
=> 2x = 12
=> x = 12 : 2 = 6
Ta có : 3x - 7/3 - 2x - 1/2 = 7 .
=> x ( 3 - 2 ) - ( 7/3 + 1/2 ) = 7 .
=> x - ( 14/6 + 3/6 ) = 7 .
=> x - 17/6 = 7 .
=> x = 7 + 17/6 .
=> x = 59/6 .
vậy x = 59/6 .
\(3x-\frac{7}{3}-2x-\frac{1}{2}=7\)
\(\Leftrightarrow\left(3x-2x\right)-\left(\frac{7}{3}+\frac{1}{2}\right)=7\)
\(\Leftrightarrow x-\frac{17}{6}=7\)
\(\Leftrightarrow x=7+\frac{17}{6}\)
\(\Leftrightarrow x=\frac{59}{6}\)
2/5.3x-1/2-1/4=1/5
=>2/5.3x-1/4=1/5
=>2/5.3x=1/5+1/4
=>2/5.3x=9/20
=>3.x=9/20:2/5
=>3.x=9/8
=>x=9/8:3
=>x=3/8
vay x=3/8
2/5.3x-1/2-1/4 = 1/5
=> 2/5.3x = 1/5+1/4+1/2
2/5.3x = 19/20
3x = (19/20):(2/5)
3x = 19/8
x = (19/8):3
x = 19/24
\(3^{x-1}+5.3^{x-1}=486\)
\(\Rightarrow3^{x-1}.\left(5+1\right)=486\)
\(3^{x-1}.6=486\)
\(3^{x-1}=81\)
\(3^{x-1}=3^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)
<=> 3x-1 +5.3x-1 =486
<=> 3x-1 . (1+5) = 486
<=> 3x-1 . 6 =486
<=> 3x-1 = 486 :6
<=> 3x-1 = 81
<=> 3x-1 = 34
<=> X-1=4
<=> X = 4+1
<=> X=5