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Ta có:
\(C= 4+44+444+......+4444444444\)
\(C= 4.(10.1+9.10+8.100+7.1000+...+1.1000000000\)
\(C= 4.(100+90+800+7000+60000+500000+4000000+30000000+200000000+1000000000)\)
\(C=4.12345678900\)
\(C=4938271600\)
Tương tự.
1).( 27,56 x 35 ) + ( 27,56 x 67 ) - ( 27,56 x 2)
= (964 + 1846,52) - 55,12
=2810,52 - 55,12
= 2755,4
2).( 4x 35 ) x ( 25 x 5 ) x 2
= ( 140 x 125 ) x2
= 17500 x 2
=35000
4). 3/10
5). 1188
6). 61/6
A = 2/1*5 + 2/5*9 + ... + 2/101*105
= 1/2(4/1*5 + 4/5*9 + ... + 4/101*105)
= 1/2(1 - 1/5 + 1/5 - 1/9 + ... + 1/101 - 1/105)
= 1/2(1 - 1/105)
= 1/2 * 104/105 = 52/105
Sửa câu b. Phân số thứ 2 phải là 4/5*8
B = 4/2*5 + 4/5*8 + ... + 4/47*50
= 4/3(3/2*5 + 3/5*8 + ... + 3/47*50)
= 4/3(1/2 - 1/5 + 1/5 - 1/8 + ... + 1/47 - 1/50)
= 4/3(1/2 - 1/50)
= 4/3 * 24/50 = 16/25
\(\frac{3}{5}+\frac{3}{11}-\left(\frac{-3}{7}\right)+\frac{2}{97}-\frac{1}{35}-\frac{3}{4}+\frac{22}{44}\)
\(=\frac{3}{5}+\frac{3}{11}+\frac{3}{7}+\frac{2}{97}-\frac{1}{35}-\frac{3}{4}+\frac{22}{44}\)
\(=\frac{3}{5}+\frac{3}{7}-\frac{1}{35}+\frac{3}{11}-\frac{3}{4}+\frac{22}{44}+\frac{2}{97}\)
\(=\left(\frac{3}{5}+\frac{3}{7}-\frac{1}{35}\right)+\left(\frac{3}{11}-\frac{3}{4}+\frac{22}{44}\right)+\frac{2}{97}\)
\(=\left(\frac{21}{35}+\frac{15}{35}-\frac{1}{35}\right)+\left(\frac{12}{44}-\frac{33}{44}+\frac{22}{44}\right)+\frac{2}{97}\)
\(=\frac{35}{35}+\frac{1}{44}+\frac{2}{97}\)
\(=1+\left(\frac{1}{44}+\frac{2}{97}\right)\)
\(=1+\left(\frac{97}{4268}+\frac{88}{4268}\right)\)
\(=1+\frac{185}{4268}=1\frac{185}{4268}\)
Chúc bạn học tốt
Trả lời:
\(\frac{3}{5}+\frac{3}{11}-\left(\frac{-3}{7}\right)+\frac{2}{97}-\frac{1}{35}-\frac{3}{4}+\frac{22}{44}\)
\(=\frac{3}{5}+\frac{3}{11}+\frac{3}{7}+\frac{2}{97}-\frac{1}{35}-\frac{3}{4}+\frac{22}{44}\)
\(=\left(\frac{3}{5}+\frac{3}{7}-\frac{1}{35}\right)+\left(\frac{3}{11}-\frac{3}{4}+\frac{22}{44}\right)+\frac{2}{97}\)
\(=1+\frac{1}{44}+\frac{2}{97}\)
\(=\frac{4453}{4268}\)