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\(\frac{-5}{6}\)\(+\)\(\frac{4}{9}\)\(\times\)\(\left(\frac{5}{4}-\frac{2}{3}\right)\)\(\times\)\(\left(-3\right)^2\)\(+\)\(\frac{5}{9}\)\(\times\)\(30\%\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{4}{9}\)\(\times\)\(\frac{7}{12}\)\(\times\)\(9\)\(+\)\(\frac{5}{9}\)\(\times\)\(\frac{3}{10}\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{7}{3}\)\(+\)\(\frac{5}{9}\)\(\times\)\(\frac{3}{10}\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{7}{3}\)\(+\)\(\frac{1}{6}\)
\(=\)\(\frac{-5}{6}\)\(+\)\(\frac{1}{6}\)\(+\)\(\frac{7}{3}\)
\(=\)\(\frac{-2}{3}\)\(+\)\(\frac{7}{3}\)
\(=\)\(\frac{5}{3}\)
Bài 4:
\(\Leftrightarrow n+1\in\left\{1;3\right\}\)
hay \(n\in\left\{0;2\right\}\)
\(\left(n+4\right)⋮\left(n+1\right)\Rightarrow\left(n+1\right)+3⋮\left(n+1\right)\)
\(\Rightarrow\left(n+1\right)\inƯ\left(3\right)=\left\{-3;-1;1;3\right\}\)
Mà \(n\in N\)
\(\Rightarrow n\in\left\{0;2\right\}\)
\(a,49,8-48,5+47,2-45,9+44,6-43,3+42-40,7\)
\(< =>1,3+1,3+1,3+1,3\)
\(< =>5,2\)
\(b,1,3-3,2+5,1-7+8,9-10,8+12,7-14,6+16,5\)
\(< =>-1,9+-1,9+-1,9+-1,9+16,5\)
\(< =>-7,6+16,5\)
\(< =>8,9\)
chuc ban hoc tot :))
3,2 . ( 5,1 + 2,52 - 3 + 4 . 2,5 ) -3,6 :9
= 3,2 . ( 5,1 + 2,52 - 3 + 10) - 0,4
= 3,2 . 14,62 - 0,4
= 46,784 - 0,4
= 46,384
cảm ơn