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[3(x + 2).7].4 = 120
3(x + 2).7 = 120 : 4
3(x + 2) = 30 : 7
x + 2 = \(\frac{30}{7}:3\)
x = \(\frac{10}{7}-2\)
x = \(\frac{5}{7}\)
\(\left[3\left(x+2\right).7\right].4=120\)
\(\Rightarrow3\left(x+2\right)=120:4:7=\frac{30}{7}\)
\(\Rightarrow x+2=\frac{30}{7}.\frac{1}{3}=\frac{10}{7}\)
\(\Rightarrow x=\frac{10}{7}-2=-\frac{4}{7}\)
`@` `\text {Ans}`
`\downarrow`
`a,`
`(x-1954) \times 5=50`
`x-1954 = 50 \div 5`
`x-1954 = 10`
`x=10 + 1954`
`x= 1964`
`B.`
`48 - 40 \times x=8`
`40 \times x=48-8`
`40 \times x = 40`
` x=40 \div 40`
`x=1`
`C.`
`2+70 \div x = 3`
`70 \div x = 3-2`
`70 \div x = 1`
`x=70 \div 1`
`x=70`
`D. [3 \times (x+2) \div 7] \times 4=120`
`3 \times (x+2) \div 7 = 120 \div 4`
`3 \times (x+2) \div 7 =30`
`3 \times (x+2) = 30 \times 7`
`3 \times (x+2)=210`
`x+2=210 \div 3`
`x+2=70`
`x=70-2`
`x=68`
`E.`
`7,2 \div [ (0,6 \times x+8) \div 20 + 59] = 0,12?` Thiếu ngoặc bạn nhé._.
\(a,\left(x-1954\right)\times5=50\\ x-1954=50:5\\ x-1954=10\\ x=1954+10\\ x=1964\\b.48-40\times x=8\\40\times x=48-8\\40\times x=40\\ x=40:40\\ x=1 \\ c.2+70:X=3\\ 70:x=3-2\\ 70:x=1\\ x=70:1\\ x=70\\ d,\left[3\times\left(x+2\right):7\right]\times4=120\\ 3\times\left(x+2\right):7-120:4\\ 3\times\left(x+2\right):7=30\\ \left(x+2\right):7=30:3\\ \left(x+2\right):7=10\\ x+2=10\times7\\ x+2=70\\ x=70-2\\ x=68\)
\(\left[3.\left(x+2\right):7\right].4=120\)
\(\Leftrightarrow\left[3.\left(x+2\right):7\right]=30\)
\(\Leftrightarrow3.\left(x+2\right)=210\)
\(\Leftrightarrow\left(x+2\right)=70\)
\(\Leftrightarrow x=68\)
Vậy \(x=68\)
[3.(x+2):7]=120:4=30
3.(x+2)=30x7=210
x+2=210:3=7
x=7-2
x=5
vậy x =5
(1-2+3-4+5-6+7-8+...+101-102+103) * x-120=2012
[ -1 + ( -1 ) ... ( -1 ) + 103] * x -120 = 2012
( -1 x 51 + 103 ) * x - 120 = 2012
( -51 +103) * x = 2012 + 120
52 * x =2132
x= 2132 : 52
x= 41
\(\left[12\cdot15-x\right]\cdot\frac{1}{4}=120\cdot\frac{1}{4}\)
\(\Leftrightarrow\left[180-x\right]\cdot\frac{1}{4}=30\)
\(\Leftrightarrow180-x=30:\frac{1}{4}\)
\(\Leftrightarrow180-x=120\)
\(\Leftrightarrow x=60\)
a/ \(\frac{x}{2}+\frac{x}{3}+\frac{x}{4}=180\)
\(\Leftrightarrow x\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}\right)=180\)
\(\Leftrightarrow\frac{13}{12}x=180\)
\(\Leftrightarrow x=\frac{2160}{13}\)
b/ \(\frac{1}{x.2}+\frac{2}{x.3}+\frac{3}{x.4}=120\)
\(\Leftrightarrow\frac{1}{x}\left(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}\right)=120\)
\(\Leftrightarrow\frac{1}{x}.\frac{23}{12}=120\)
\(\Leftrightarrow\frac{1}{x}=\frac{1440}{23}\)
\(\Leftrightarrow x=\frac{23}{1440}\)
3x(x+2):7=120:4=30
3x(x+2)=30x7=210
( 3 x ( x + 2 ) : 7 ) x 4 = 120
( 3 x ( x + 2 ) : 7 ) = 120 : 4
3 x ( x + 2 ) : 7 = 30
( x + 2 ) : 7 = 30 : 3
( x + 2 ) : 7 = 10
( x + 2 ) = 10 x 7
x + 2 = 70
x = 70 - 2
x = 68