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Bài 1:
a: x+1/2=5/6
nên x=5/6-1/2=1/3
b: x+1/4=3/4
nên x=3/4-1/4=2/4=1/2
c: x+3/10=1/2
nên x=1/2-3/10=5/10-3/10=1/5
d: x+1/4=3/8
nên x=3/8-1/4=3/8-2/8=1/8
\(\dfrac{5}{7}\times\dfrac{3}{5}-\dfrac{10}{14}\times\dfrac{2}{5}\)
\(=\dfrac{3}{7}-\dfrac{2}{7}\)
\(=\dfrac{1}{7}\)
Chúc bạn học tốt
a)
`3/5xx3/2`
`=3/5xx2/3`
`=2/5`
b)
`3/7:3/14`
`=3/7xx14/3`
`=2`
c)
`5/7xx7/10`
`=1/2`
d)
`5/11xx33/15`
`=5/11xx11/5`
`=1`
\(a,\dfrac{3}{5}:\dfrac{3}{2}=\dfrac{3}{5}\times\dfrac{2}{3}=\dfrac{6}{15}=\dfrac{2}{5}\)
\(b,\dfrac{3}{7}:\dfrac{3}{14}=\dfrac{3}{7}\times\dfrac{14}{3}=\dfrac{42}{21}=42:21=2\)
\(c,\dfrac{5}{7}\times\dfrac{7}{10}=\dfrac{35}{70}=\dfrac{1}{2}\)
\(d,\dfrac{5}{11}\times\dfrac{33}{15}=\dfrac{165}{165}=165:165=1\)
5/9x12/7=20/21
6/5:8/3=9/20
9/20x5/12=3/16
15/16:25/24=9/10
14x5/21=10/3
10:5/3=6
5/3:10=1/6
5/9 x 12/7 = 60/63
6/5 : 8/3 = 6/5 x 3/8 = 9/20
9/20 x 5/12 = 3/16
15/16 : 25/24 = 15/16 x 24/25 = 9/10
14 x 5/21 = 60/21
10 : 5/3 = 10 x 3/5 = 6
5/3 : 10 = 5/3 x 1/10 = 1/6
Bài 1: Tính
a, 1/2 x 2/3 x 3/4 = 1/4
b, 7/8 x 8/9 x 9/10 = 7/10
c, 5/14 x 7/15 x 28/7 = 2/3
d, 2 x 1/2 x 3 x 1/3 x 4 x 1/4 x 5 x 1/5 = 1
Bài 2: Tính
a, 7/20 - ( 5/8 - 3/5 ) = 7/20 - 1/40 = 14/40 - 1/40 = 13/40
b, 5/6 + ( 5/9 - 1/4 ) = 5/6 + 11/36 = 30/36 + 11/36 = 41/36
c, 9/10 - ( 2/5 + 3/10 ) + 7/20 = 9/10 - 7/10 + 7/20 = 2/10 + 7/20 = 4/20 + 7/20 = 11/20.
Bài 3: Tìm x:
a, 1/2 + x = 5/6
x = 5/6 - 1/2
x = 1/3
b, 5/6 - x = 1/3
x = 5/6 - 1/3
x = 1/2
c, x - 1/mấy vậy bạn
d, 1/3 x x = 1/6
x = 1/6 : 1/3
x = 1/2
(15x1-15) x) (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= (15-15) x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= 0 x (10+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20)
= 0
= (15 - 15)\(\times\)(10 +1 +2 +3 +4 +5 +6 +7 +8 +9 +10 +11 +12 +13 +14 +15 +16 +17 +18 +19 +20)
= 0\(\times\)(10 +1 +2 +3 +4 +5 +6 +7 +8 +9 +10 +11 +12 +13 +14 +15 +16 +17 +18 +19 +20)
= 0
\((\)125-120\()\)x45
5x45=225
\(\dfrac{30x25x7x8}{75x8x12x14}\)=\(\dfrac{10\cdot1\cdot7\cdot1}{1\cdot1\cdot1\cdot12\cdot2}\)=\(\dfrac{70}{24}\)
\(=\dfrac{7}{10}\left(3+5+2\right)=\dfrac{7}{10}\cdot10=7\)
`3xx7/10+7/10xx5+2xx14/20`
`=3xx7/10+7/10xx5+2xx7/10`
`=7/10xx(3+5+2)=7/10xx10=7`