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15 tháng 3 2022

\(a,\dfrac{3}{5}+\dfrac{-5}{9}=\dfrac{27-25}{45}=\dfrac{2}{49}.\)

\(c,\dfrac{-27}{23}+\dfrac{5}{21}+\dfrac{4}{23}+\dfrac{16}{21}+\dfrac{1}{2}=\dfrac{-23}{23}+\dfrac{21}{21}+\dfrac{1}{2}=-1+1+\dfrac{1}{2}=\dfrac{1}{2}.\)

\(d,\dfrac{-8}{9}+\dfrac{1}{9}.\dfrac{2}{9}+\dfrac{1}{9}.\dfrac{7}{9}=\dfrac{-8}{9}+\dfrac{1}{9}.\left(\dfrac{2}{9}+\dfrac{7}{9}\right)=\dfrac{-8}{9}+\dfrac{1}{9}.1=\dfrac{-8+1}{9}=\dfrac{-7}{9}.\)

1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)

\(=2155-174-2155-68+174\)

=-68

2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)

\(=-25\cdot\left(72-21+49\right)\)

\(=-25\cdot100=-2500\)

7 tháng 7 2021

\(1\dfrac{4}{23}+\left(\dfrac{5}{21}-\dfrac{4}{23}\right)+\dfrac{16}{21}-\dfrac{1}{2}\)

\(=1\dfrac{4}{23}-\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{16}{21}+\dfrac{1}{2}\)

\(=1+1-\dfrac{1}{2}\)

\(=\dfrac{3}{2}\)

7 tháng 7 2021

1 4/23 + ( 5/21-4/23 ) + 16/21 - 1/2
=1 4/23 - 4/23 + 5/21 + 16/21 + 1/2
= 1+1-1/2
=3/2

3 tháng 11 2019

(-3/4+2/3):5/11+(-1/4+1/3):5/11

15 tháng 6 2020

a)|x-13|-35-45=-47

b)(4+x).(x+3)=0

c)25-(5-x)=120-(28-5)

8 tháng 3 2023

`a)1 4/23 + ( 5/21-4/23)+16/21-1/2`

`=27/23+5/21-4/23+16/21-1/2`

`=(27/23-4/23)+(5/21+16/21)-1/2`

`=23/23+21/21-1/2`

`=1+1-1/2`

`=2-1/2`

`=4/2-1/2`

`=3/2`

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`b)75%-(5/2+5/3)+(-1/2)^3`

`=3/4-5/2+5/3+(-1/8)`

`=(3/4-5/2-1/8)+5/3`

`=(6/8-20/8-1/8)+5/3`

`=-15/8+5/3`

`=-45/24+40/24`

`=-5/24`

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`c)-3/4(-55/9).8/11`

`=-3/4.(-40/9)`

`=-10/3`

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`d)-3/8 . 6/13 + 7/13 . (-3/8) + 1 3/8`

`= -3/8 . (6/13 + 7/13) + 11/8`

`= -3/8 . 13/13 + 11/8`

`= -3/8 .1 + 11/8`

`= -3/8 + 11/8`

`= 8/8`

`=1`

a: =1/8-1/8+2/5=2/5

b: =(-1/15-14/15)+(23/27+31/27)=2-1=1

c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)

d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)