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Ta có : \(\frac{\left(\frac{2}{5}\right)^9.10^9-\left(\frac{-9}{4}\right)^5:\left(\frac{-3}{16}\right)^{10}}{4^{12}+16^9}\)
=\(\frac{\left(\frac{2}{5}.10\right)^9-\left[\left(\frac{-3}{2}\right)^2\right]^5:\left(\frac{-3}{16}\right)^{10}}{\left(2^2\right)^{12}+\left(2^4\right)^9}\)=\(\frac{4^9-\left(\frac{-3}{2}\right)^{10}:\left(\frac{-3}{16}\right)^{10}}{2^{24}+2^{36}}\)=\(\frac{4^9-\left[\left(\frac{-3}{2}\right):\left(\frac{-3}{16}\right)\right]^{10}}{2^{24}\left(1+2^{12}\right)}\)
=\(\frac{\left(2^2\right)^9-8^{10}}{2^{24}\left(1+2^{12}\right)}\)=\(\frac{\left(2^2\right)^9-\left(2^3\right)^{10}}{2^{24}\left(1+2^{12}\right)}\)=\(\frac{2^{18}-2^{30}}{2^{24}\left(1+2^{12}\right)}\)=\(\frac{2^{18}\left(1-2^{12}\right)}{2^{24}\left(1+2^{12}\right)}\)=\(\frac{1-2^{12}}{2^6\left(1+2^{12}\right)}\)
Không biết đúng hong nha!
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
a: \(=\dfrac{-8}{9}-\dfrac{6}{5}+\dfrac{8}{9}=-\dfrac{6}{5}\)
c: \(=\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}\)
a) 32.x+2=1342176728
32.x=134217728-2
32.x=134217726
x=134217726:32
x=4194303,938