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a) \(\frac{24}{x}:\frac{8}{3}=\frac{3}{5}\) \(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\) \(\frac{24}{x}=\frac{8}{5}\) \(x=24.5:8\) \(x=15\)
b) Đề bài sai rồi
a: =>6/x=x/24
=>x^2=144
=>x=12 hoặc x=-12
b: =>x(1-7/12+3/8)=5/24
=>x*19/24=5/24
=>x=5/24:19/24=5/19
c: =>(x-1/3)^2=1+3/4+1/2=9/4
=>x-1/3=3/2 hoặc x-1/3=-3/2
=>x=11/6 hoặc x=-7/6
d: =>(x-3)^2=16
=>x-3=4 hoặc x-3=-4
=>x=-1 hoặc x=7
e: =>9/x=-1/3
=>x=-27
f: =>x-1/2=0 hoặc -x/2-3=0
=>x=1/2 hoặc x=-6
a)\(x+\frac{1}{2}:\left(-\frac{3}{4}\right)=-\frac{5}{4}\)
\(x+-\frac{2}{3}=-\frac{5}{4}\)
\(x=-\frac{5}{4}-\left(-\frac{2}{3}\right)\)
\(x=-\frac{7}{12}\)
Vậy \(x=-\frac{7}{12}\)
b)Câu b mk ko hiểu bn ghi đề sao vậy (5 3/8)
a, => x + \(\frac{-2}{3}=\frac{-5}{4}\)
=>x = \(\frac{15}{8}\)
câu b mik cx làm đc nhưng mik gại ghi lắm
`x/8 = 3/4 +(-5/8)`
`=>x/8 = 6/8 +(-5/8)`
`=>x/8 = 1/8`
`=>x=1`
`-----`
`x/12 =3/4 +(-2/3)`
`=>x/12 = 9/12 + (-8/12)`
`=> x/12=1/12`
`=>x=1`
`----`
`1+11/13=24/x`
`=> 13/13 +11/13=24/x`
`=> 24/13 =24/x`
`=>x=13`
`----`
`x/6 -3/4=1/12`
`=>x/6 = 1/12 +3/4`
`=>x/6 = 1/12 + 9/12`
`=>x/6 = 10/12`
`=>x/6= 5/6`
`=>x=5`
e) 5(3-2x)+5(x-4)=6-4x
⇔15-10x+5x-20-6+4x=0
⇔-x-11=0
hay -x=11
⇔x=-11
Vậy: x=-11
g) 2(4x-8)-7(3+x)=|-4|(3-2)
⇔8x-16-21-7x=4
⇔x-37=4
hay x=41
Vậy: x=41
k) -7(5-x)-2(x-10)=15
⇔-35+7x-2x+20=15
⇔5x-15=15
hay 5x=30
⇔x=6
Vậy: x=6
m) -4(x+1)+(89x-3)=24
⇔-4x-4+89x-3=24
⇔85x-7=24
⇔85x=31
hay \(x=\frac{31}{85}\)(ktm x∈Z)
Vậy: x∈∅
q) 10(x-7)-8(x+5)=6*(-5)+24
⇔10x-70-8x-40=-6
⇔2x-110=-6
⇔2x=104
hay x=52
Vậy: x=52
\(\dfrac{24}{x}:\dfrac{8}{3}=\dfrac{3}{5}\)
\(\dfrac{24}{x}=\dfrac{3}{5}.\dfrac{8}{3}\)
\(\dfrac{24}{x}=\dfrac{8}{5}\)
\(\dfrac{24}{x}=\dfrac{24}{15}\)
=>x=5
Vậy x=5
\(x+3\dfrac{1}{2}+x=24\dfrac{1}{4}\)
\(\left(x+x\right)+3\dfrac{1}{2}=24\dfrac{1}{4}\)
\(x.2+\dfrac{7}{2}=\dfrac{97}{4}\)
\(x.2=\dfrac{97}{4}-\dfrac{7}{2}\)
\(x.2=\dfrac{97}{4}-\dfrac{14}{4}\)
\(x.2=\dfrac{83}{4}\)
\(x=\dfrac{83}{4}:2\)
\(x=\dfrac{83}{4}.\dfrac{1}{2}\)
\(x=\dfrac{83}{8}\)
\(x=10\dfrac{3}{8}\)