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\(\frac{3}{5}+\frac{6}{11}+\frac{7}{13}+\frac{2}{5}+\frac{16}{11}+\frac{19}{13}\)
\(=\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{6}{11}\frac{16}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)\)
\(=1+2+2\)
\(=5\)
1=ĐS=1
2=ĐS=2000
3=ĐS=0
4=ĐS=7036
K MÌNH NHA
a.
(1 + 3 + 5 + ... + 2007 + 2009 + 2011) x (125125 x 127 - 127127 x 125)
= (1 + 3 + 5 + ... + 2007 + 2009 + 2011) x 0
= 0
b.
\(\frac{2006\times125+1000}{126\times2006-1006}=\frac{2006\times125+1000}{125\times2006+1\times2006-1006}=\frac{2006\times125+1000}{125\times2006+1000}=1\)
a,
( 1+3+5+7+…+2003+2005) x (125 125 x 127 – 127 127 x 125)
= ( 1+3+5+7+…+2003+2005) x (125 x 1001 x 127 – 127 x 1001x 125)
= ( 1+3+5+7+…+2003+2005) x 0 = 0
\(1-\dfrac{1}{x}=\dfrac{1994}{1995}\)
\(\dfrac{1}{x}=\dfrac{1}{1995}\)
x= 1995
\(\dfrac{2}{1\times3}\) + \(\dfrac{2}{3\times5}\) +...+ \(\dfrac{2}{\left(x-2\right)\times x}\) = \(\dfrac{1994}{1995}\)
\(\dfrac{1}{1}\) - \(\dfrac{1}{3}\) + \(\dfrac{1}{3}\) - \(\dfrac{1}{5}\) +...+ \(\dfrac{1}{x-2}-\dfrac{1}{x}\) = \(\dfrac{1994}{1995}\)
1 - \(\dfrac{1}{x}\) = \(\dfrac{1994}{1995}\)
\(\dfrac{1}{x}\) = 1 - \(\dfrac{1994}{1995}\)
\(\dfrac{1}{x}\) = \(\dfrac{1}{1995}\)
\(x\) = 1995