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2) \(\left(\dfrac{1}{6}+2\dfrac{1}{2}-10,75\right)\cdot x-7=\left(\dfrac{2}{5}+\dfrac{3}{8}+0,025\right):0,1\)
\(\left(\dfrac{1}{6}+\dfrac{5}{2}-\dfrac{43}{4}\right)x-7=\left(\dfrac{2}{5}+\dfrac{3}{8}+\dfrac{1}{40}\right):\dfrac{1}{10}\)
\(-\dfrac{97}{12}x-7=\dfrac{4}{5}\cdot10\)
\(-\dfrac{97}{12}x=8+7\\ -\dfrac{97}{12}x=15\\ x=15:\left(-\dfrac{97}{12}\right)\\ x=-\dfrac{180}{97}\)
\(\left(1+2\frac{1}{12}-10,75\right)x-7=\left(\frac{2}{5}+\frac{8}{5}+0,225\right):0,1\)
\(=\left(\frac{37}{12}-\frac{129}{12}\right)x-7=\left(2+\frac{9}{40}\right).10\)
\(=-\frac{23}{3}x=\frac{28}{4}+\frac{89}{4}=\frac{201}{4}\)
\(x=\frac{201}{4}:\left(-\frac{23}{3}\right)=\frac{201}{4}.\left(-\frac{3}{23}\right)=-\frac{603}{92}\)
\(\left(1+2\frac{1}{1,25}\right)x-7=\frac{89}{4}\)
\(\left(1+\frac{14}{5}\right)x-7=\frac{89}{4}\)
toi day mih bi luon
\(1,\\ x+\dfrac{1}{2}=-\dfrac{5}{3}\\ x=-\dfrac{5}{3}-\dfrac{1}{2}\\ x=-\dfrac{13}{6}\\ Vậyx=-\dfrac{13}{6}\)
\(2,\\ \dfrac{1}{3}-x=\dfrac{3}{5}\\ x=\dfrac{1}{3}-\dfrac{3}{5}\\ x=-\dfrac{4}{15}\\ Vậyx=-\dfrac{4}{15}\)
\(3,\\ 3-4+x=\dfrac{7}{2}\\ -1+x=\dfrac{7}{2}\\ x=\dfrac{7}{2}+1\\ x=\dfrac{9}{2}\\ Vậyx=\dfrac{9}{2}\)
\(4,\\ x-\dfrac{4}{3}=-\dfrac{7}{9}\\ x=-\dfrac{7}{9}+\dfrac{4}{3}\\ x=\dfrac{15}{27}\\ Vậyx=\dfrac{15}{27}\)
\(5,\\ x-\left(-\dfrac{7}{3}\right)=\dfrac{5}{6}\\ x=\dfrac{5}{6}-\dfrac{7}{3}\\ x=-\dfrac{27}{18}\\ Vậyx=-\dfrac{27}{18}\)
\(6,\\ x-\dfrac{1}{5}=\dfrac{9}{10}\\ x=\dfrac{9}{10}+\dfrac{1}{5}\\ x=\dfrac{11}{10}\\ Vậyx=\dfrac{11}{10}\)
\(7,\\ x+\dfrac{5}{12}=\dfrac{3}{8}\\ x=\dfrac{3}{8}-\dfrac{5}{12}\\ x=-\dfrac{1}{24}\\ Vậyx=-\dfrac{1}{24}\)
\(8,\\ x+\dfrac{5}{4}=\dfrac{7}{6}\\ x=\dfrac{7}{6}-\dfrac{5}{4}\\ x=-\dfrac{9}{24}\\ Vậyx=-\dfrac{9}{24}\)
\(9,\\ x-\dfrac{2}{7}=\dfrac{1}{35}\\ x=\dfrac{1}{35}+\dfrac{2}{7}\\ x=\dfrac{11}{35}\\ Vậyx=\dfrac{11}{35}\\ 10,\\ x-\dfrac{1}{5}=-\dfrac{7}{10}\\ x=-\dfrac{7}{10}+\dfrac{1}{5}\\ x=-\dfrac{1}{2}\\ Vậyx=-\dfrac{1}{2}\)
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