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=(1/13+12/13)+(2/13+11/13)+(3/13+10/13)+......(6/13+7/13)
=1+1+1+1+1+1
=6
\(=\frac{1+2+3+...+12}{13}\)
\(=\frac{\left(12+1\right)+\left(11+2\right)+..+\left(5+7\right)+6}{13}\)
\(=\frac{12+12+12+12+12+6}{13}\)
\(=\frac{12.5+6}{13}\)
\(=\frac{66}{13}\)
Trả lời
\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{1}{14+15}\)
Hay
\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+15}\)
mong xem lại hộ cái
\(\frac{4}{3}\cdot7+\frac{5}{7}\cdot12+\frac{1}{12}\cdot13+\frac{7}{13}\cdot20+\frac{3}{20}\cdot23+\frac{9}{23}\cdot32\)
BẠN VIÊT THẾ NÀY THÌ MN DỄ HIỂU HƠN NHÉ
=\(\frac{4}{3}\times\left[7+\frac{5}{7}\right]\times\left[12+\frac{1}{12}\right]\times\left[13+\frac{7}{13}\right]\times\left[20+\frac{3}{20}\right]\times23\)
\(=\frac{4}{3}\times\frac{12}{7}\times\frac{13}{12}\times\frac{20}{13}\times\frac{23}{20}\times23\)
\(\frac{4}{3}\times\left[\frac{12}{7}\times\frac{13}{12}\right]\times\left[\frac{20}{13}\times\frac{23}{20}\right]\times23\)
\(=\frac{4}{3}\times\frac{13}{7}\times\frac{23}{13}\times23\)
\(\frac{4}{3}\times\left[\frac{13}{7}\times\frac{23}{13}\right]\times23\)
\(\frac{4}{3}\times\frac{23}{7}\times23\)
con lai ban tu tinh nhe
1.3.77−1+3.7.99−3+7.9.1313−7+9.13.1515−9+\frac{19-13}{13.15.19}+13.15.1919−13
=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31−3.71+3.71−7.91+7.91−9.131+9.131−13.151+13.151−15.191
=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31−15.191=28595−2851=28594
b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61.(1.3.76+3.7.96+7.9.136+9.13.156+13.15.196)
làm giống như trên
c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81.(1.2.31+2.3.41+3.4.51+...+48.49.501)
=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161.(1.2.32+2.3.42+3.4.52+...+48.49.502)
=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161.(1.2.33−1+2.3.44−2+3.4.55−3+...+48.49.5050−48)
=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161.(1.21−2.31+2.31−3.41+3.41−4.51+...+48.491−49.501)
=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161.(21−24501)=161.(24501225−24501)=4900153
d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75.(1.5.87+5.8.127+8.12.157+...+33.36.407)
=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75.(1.5.88−1+5.8.1212−5+8.12.1515−8+...+33.36.4040−33)
=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75.(1.51−5.81+5.81−8.121+8.121−12.151+...+33.361−36.401)
=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75.(51−14401)=75.(1440288−14401)=28841
P/S: . là nhân nha
a) 35 x 12 + 65 x 13
= 35 x 12 + 65 x (12+1)
=35 x 12 + 65 x 21 + 65
=12 x (65 + 35) + 65
= 12 x 100 + 65
= 1200 + 65
= 1265
b) (37 x 13 -13) : (24 + 37 x 12)
= [ 37 x (12+1) - 13 ] : (24 + 37 x 12)
=( 37 x 12 + 37 - 13) : ( 24 +37 x 12)
=( 37 x 12 +24) : (24 + 37 x 12)
=\(1\)
Ta có nhận xét phần b hai tích chia cho nhau mà 2 tích giống nhau vậy kết quả là \(1\)
35 x 12 + 65 x 13 = 1265
( 37 x 13 - 13) : (24 + 37 x 12) = 1
\(\frac{13}{19}\cdot\frac{1}{12}+\frac{13}{19}\cdot\frac{21}{12}-\frac{13}{19}\cdot\frac{2}{3}\)
\(=\frac{13}{19}\cdot\left(\frac{1}{12}+\frac{21}{12}-\frac{2}{3}\right)\)
\(=\frac{13}{19}\cdot\frac{7}{6}\)
\(=\frac{91}{114}\)