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1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96 + 1/192 + 1/384 = 85/128
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}\)
\(=\frac{1}{2}+\frac{1}{8}+\frac{1}{32}\)
\(=\frac{5}{8}+\frac{1}{32}\)
\(=\frac{21}{32}\)
1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96 + 1/192
= 127/192
k minh di , xin day
\(\frac{1}{3}\)+ \(\frac{1}{6}\)+ \(\frac{1}{12}\)+\(\frac{1}{24}\)+\(\frac{1}{48}\)+\(\frac{1}{96}\)
= ( \(\frac{1}{3}\)+\(\frac{1}{6}\)) + ( \(\frac{1}{12}\)+ \(\frac{1}{24}\)) + ( \(\frac{1}{48}\)+\(\frac{1}{96}\))
= \(\frac{1}{2}\) + \(\frac{1}{8}\) + \(\frac{1}{32}\)
= \(\frac{5}{8}\) + \(\frac{1}{32}\)
= \(\frac{21}{32}\)
B1:Tính nhanh
1/3+1/6+1/12+1/24+1/48+1/96=?
Nhớ viết cách tính ra nhé
Ai làm nhanh nhất thì mình tk cho
B = 1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96
2B = 2(13+16+112+124+148+196)=23+13+16+112+124+148
B = 2B - B
= (23+13+16+112+124+148)−(13+16+112+124+148+196)
= (23+13+16+112+124+148)−13−16−112−124−148−196
= 23−196=21/32
\(a,\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+....+\frac{1}{384}\)
\(\text{Đ}\text{ặt}\)\(A=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+...+\frac{1}{384}\)
\(2A=\frac{1}{3}+\frac{1}{6}+\frac{1}{12}+....+\frac{1}{192}\)
\(2A-A=\frac{1}{3}-\frac{1}{384}\)
a đề sai
b)Đặt A=1/4x7 + 1/7x10 + 1/10x13 +...........+ 1/19x22
\(3A=3\left(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{19.22}\right)\)
\(3A=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{19}-\frac{1}{22}\)
\(3A=\frac{1}{4}-\frac{1}{22}\)
\(A=\frac{9}{44}:3\)
\(A=\frac{3}{44}\)
Đặt tổng các phân số trên là A ta có
\(\frac{A}{2}=\frac{1}{6}+\frac{1}{12}+\frac{1}{24}+\frac{1}{48}+\frac{1}{96}+\frac{1}{192}\)
\(\frac{A}{2}=A-\frac{A}{2}=\frac{1}{3}-\frac{1}{192}=\frac{63}{192}\Rightarrow A=\frac{2x63}{192}=\frac{126}{192}=\frac{21}{32}\)
1/3 + 1/6 + 1/12 + 1/24 + 1/48 + 1/96
= 1x32/2x32 + 1x16/6x16 + 1x8/12x8 + 1x4/24x4 + 1x2/48x2 + 1/96
= 32/96 + 16/96 + 8/96 + 4/96 + 2/96 + 1/96
= 63/96