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vd câu 1:
ta có x-y=4 =>x=4+y
ta có pt:
4+y/y-2=3/2
=>8+2y=3y-6
=>-y=-14
=>y=14
=>x=4+y=4+14=18
các bài khác cũng tương tự thôi bạn
\(3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(\left(3x-\frac{3}{2}\right)-\left(5x+3\right)=-x+\frac{1}{5}\)
\(3x-\frac{3}{2}-5x-3-\frac{1}{5}=-x\)
\(-2x-6,7=-x\)
\(-2x-x=6,7\)
\(-3x=6,7\)
\(x=-\frac{67}{30}\)
Vậy \(x=-\frac{67}{30}\)
=>-5x-1-1/2x+1/3=3/2x-5/6
=>-11/2x-3/2x=-5/6+2/3
=>-7x=-1/6
=>x=1/42
x . \(\frac{1}{2}\)- x.\(\frac{2}{3}\) + x.\(\frac{3}{4}\)- x. \(\frac{5}{6}\) = \(\frac{5}{6}\) -\(\frac{3}{4}\) + \(\frac{2}{3}\) -\(\frac{1}{2}\)
x . \(\frac{1}{2}\)- x.\(\frac{2}{3}\) + x.\(\frac{3}{4}\)- x. \(\frac{5}{6}\) = \(\frac{10}{12}\)-\(\frac{9}{12}\)+\(\frac{8}{12}\)-\(\frac{6}{12}\)
x . \(\frac{1}{2}\)- x.\(\frac{2}{3}\) + x.\(\frac{3}{4}\)- x. \(\frac{5}{6}\)= \(\frac{1}{4}\)=> x. (\(\frac{1}{2}\)- \(\frac{2}{3}\) + \(\frac{3}{4}\)- \(\frac{5}{6}\)) = \(\frac{1}{4}\)=> x.( \(\frac{6}{12}\)- \(\frac{8}{12}\)+\(\frac{9}{12}\)-\(\frac{10}{12}\))= \(\frac{1}{4}\)=> x. \(\frac{-1}{4}\)=\(\frac{1}{4}\)=> x = \(\frac{1}{4}\): \(\frac{-1}{4}\)=> x = -1=>x.(1/2-2/3+3/4)=1/4
=>x.7/12=1/4
=>x=1/4:7/12
=>x=1/4.12/7
=>x=3/7
\(\frac{1}{2}.x+\frac{3}{5}.x=3+2\)
\(\left(\frac{1}{2}+\frac{3}{5}\right).x=5\)
\(\frac{11}{10}.x=5\)
\(x=5:\frac{11}{10}\)
\(x=\frac{50}{11}\)
1/2 . x + 3/5 . ( x -2 ) = 3
=> 1/2 . x + 3/5 x - 6/5 = 3
=> x . ( 1/2 + 3/5 ) - 6/5 = 3
=> x . 11/10- 6/5 = 3
=> x . 11/10 = 3 + 6/5
=>x . 11/10 = 21/5
=> x = 21/5 : 11/10
=> x = 42/11
\(\frac{1}{2}.x+\frac{3}{5}.\left(x-2\right)=3 \)
\(\frac{1}{2}x+\frac{3}{5}x-\frac{3}{5}.2=3\)
\(\left(\frac{1}{2}+\frac{3}{5}\right)x-\frac{6}{5}=3\)
\(\left(\frac{5}{10}+\frac{6}{10}\right).x=3+\frac{6}{5}\)
\(\frac{11}{10}.x=\frac{21}{5}\)
x =\(\frac{21}{5}:\frac{11}{10}\)
x=\(\frac{21}{5}.\frac{10}{11}\)
x-\(\frac{42}{11}\)