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\(27-\left(14-x\right)=-x+3\)
\(\Leftrightarrow\)\(27-14+x=-x+3\)
\(\Leftrightarrow\)\(13+x=-x+3\)
\(\Leftrightarrow\)\(2x=-10\)
\(\Leftrightarrow\)\(x=-5\)
Vậy...
Câu 1 :
=> 27-14+x = -x+3
=> 13+x = -x+3
=> x = -x+3-13 = -x-10
=> 10 = -x-x = -2x
=> x = 10 : (-2) = -5
Vậy x = -5
Tk mk nha
\(284:\left[314-\left(x+3\right)\right]=12.\)
\(\Leftrightarrow\left[314-\left(x+3\right)\right]=\frac{71}{3}\)
\(\Leftrightarrow\left(x+3\right)=\frac{871}{3}\)
\(\Leftrightarrow x=\frac{862}{3}\)
\(14.\left[251-\left(x-5\right)\right]=1470\)
\(\Leftrightarrow\left[251-\left(x-5\right)\right]=105\)
\(\Leftrightarrow x-5=146\)
\(\Leftrightarrow x=151\)
\(\left(120+x\right):x-15=16\)
\(\Leftrightarrow\left(120+x\right):x=31\)
\(\Leftrightarrow\left(120+x\right).\frac{1}{x}=31\)
\(\Leftrightarrow\frac{1}{x}.x+120x=31\)
\(\Leftrightarrow1+120x=31\)
\(\Leftrightarrow120x=30\)
\(\Leftrightarrow x=4\)
\(\left(135-x\right):x+24=28\)
\(\Leftrightarrow\left(135-x\right):x=4\)
\(\Leftrightarrow\left(135-x\right).\frac{1}{x}=4\)
\(\Leftrightarrow\frac{1}{x}.135-\frac{1}{x}x=4\)
\(\Leftrightarrow\frac{1}{x}135-1=4\)
\(\Leftrightarrow\frac{1}{x}135=5\)
\(\Leftrightarrow\frac{1}{x}=\frac{1}{27}\)
\(\Leftrightarrow x=27\)
\(a,-\dfrac{12}{16}-\left(\dfrac{3}{4}-x\right)=-\dfrac{5}{3}\)
\(\dfrac{3}{4}-x=-\dfrac{12}{16}-\left(-\dfrac{5}{3}\right)\)
\(\dfrac{3}{4}-x=\dfrac{11}{12}\)
\(x=\dfrac{3}{4}-\dfrac{11}{12}\)
\(x=-\dfrac{1}{6}\)
\(b,x-\dfrac{3}{7}:\dfrac{9}{14}=-\dfrac{7}{3}\)
\(x-\dfrac{3}{7}=-\dfrac{7}{3}\times\dfrac{9}{14}\)
\(x-\dfrac{3}{7}=-\dfrac{3}{2}\)
\(x=-\dfrac{3}{2}+\dfrac{3}{7}\)
\(x=-\dfrac{15}{14}\)
\(c,-\dfrac{3}{4}x+\dfrac{5}{8}x=\dfrac{1}{3}\)
\(\left(-\dfrac{3}{4}+\dfrac{5}{8}\right)x=\dfrac{1}{3}\)
\(-\dfrac{1}{8}x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\left(-\dfrac{1}{8}\right)\)
\(x=-\dfrac{8}{3}\)
12x - 14( x - 5 ) = 36
=> 12x - 14x - 70 = 36
12x - 14x = 36 + 70 = 106
chỉ bt tek