Câu hỏi của Nguyễn Phương Anh

Question

(1/27)^10 và (1/243)^7 so sánh

『ღƤℓαէїŋʉɱ ₣їɾεツ』 · Accepted Answer

$\left(\frac{1}{27}\right)^{10}\&\left(\frac{1}{243}\right)^7$$\left(\frac{1}{27}\right)^{10}=\left(\frac{1}{3^3}\right)^{10}=\frac{1}{3^{30}}$$\left(\frac{1}{243}\right)^7=\left(\frac{1}{3^5}\right)^7=\frac{1}{3^{35}}$Vậy $\left(\frac{1}{27}\right)^{10}>\left(\frac{1}{243}\right)^7$Câu trả lời: $\left(\frac{1}{27}\right)^{10}\&\left(\frac{1}{243}\right)^7$$\left(\frac{1}{27}\right)^{10}=\left(\frac{1}{3^3}\right)^{10}=\frac{1}{3^{30}}$$\left(\frac{1}{243}\right)^7=\left(\frac{1}{3^5}\right)^7=\frac{1}{3^{35}}$Vậy $\left(\frac{1}{27}\right)^{10}>\left(\frac{1}{243}\right)^7$

Arima Kousei · Answer

Ta có : $\left(\frac{1}{27}\right)^{10}=\left(\frac{1}{3^3}\right)^{10}=\frac{1}{3^{30}}$$\left(\frac{1}{243}\right)^7=\left(\frac{1}{3^5}\right)^7=\frac{1}{3^{35}}$Do : $\frac{1}{3^{30}}>\frac{1}{3^{35}}\left(3^{30}< 3^{35}\right)$$\Rightarrow\left(\frac{1}{27}\right)^{10}>\left(\frac{1}{243}\right)^7$Câu trả lời: Ta có : $\left(\frac{1}{27}\right)^{10}=\left(\frac{1}{3^3}\right)^{10}=\frac{1}{3^{30}}$$\left(\frac{1}{243}\right)^7=\left(\frac{1}{3^5}\right)^7=\frac{1}{3^{35}}$Do : $\frac{1}{3^{30}}>\frac{1}{3^{35}}\left(3^{30}< 3^{35}\right)$$\Rightarrow\left(\frac{1}{27}\right)^{10}>\left(\frac{1}{243}\right)^7$

Chúng tôi đề xuất

Tài nguyên

Ứng dụng mobile

Bảng xếp hạng

Các khóa học có thể bạn quan tâm

Yêu cầu VIP