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\(C=1.2.3+2.3.4+...+48.49.50\)
\(\Rightarrow4C=1.2.3.4+2.3.4.4+...+48.49.50.4\)
\(=1.2.3.4+2.3.4.\left(5-1\right)+...+48.49.50.\left(51-47\right)\)
\(=1.2.3.4+2.3.4.5-1.2.3.4+...+48.49.50.51-47.48.49.50\)
\(=48.49.50.51\)
\(\Rightarrow C=\frac{48.49.50.51}{4}=1499400\)
\(C=1\cdot2\cdot3+2\cdot3\cdot4+4\cdot5\cdot6+...+48\cdot49\cdot50\)
\(4C=1\cdot2\cdot3\cdot4+2\cdot3\cdot4\cdot\left(5-1\right)+...+48\cdot49\cdot50\cdot\left(51-47\right)\)
\(4C=1\cdot2\cdot3\cdot4+2\cdot3\cdot4\cdot5-1\cdot2\cdot3\cdot4+...+48\cdot49\cdot50\cdot51-47\cdot48\cdot49\cdot50\)
\(4C=48\cdot49\cdot50\cdot51\Rightarrow C=\dfrac{5997600}{4}=1499400\)
\(A=1.2.3+2.3.4+3.4.5+...+48.49.50\)
\(4A=1.2.3.4+2.3.4.4+3.4.5.4+...+48.49.50.4\)
\(4A=1.2.3.\left(4-0\right)+2.3.4.\left(5-1\right)+...+48.49.50.\left(51-47\right)\)
\(4A=1.2.3.4-0.1.2.3+2.3.4.5-1.2.3.4+...+48.49.50.51-48.48.49.50\)
\(4A=48.49.50.51\)
\(A=\dfrac{48.49.50.51}{4}=1499400\)
4F=4.[1.2.3 + 2.3.4 + 3.4.5 + 4.5.6 + . . . . . . + 48.49.50]
4F=1.2.3.4 +2.3.4.4 +3.4.5.4 +4.5.6.4 +.........+48.49.50.4
4F=1.2.3.4 +2.3.4.(5-1) + 3.4.5.(6-2) +4.5.6(7-3)+....+ 48.49.50(51-47)
4F=1.2.3.4 +2.3.4.5 --1.2.3.4 + 3.4.5.6--2.3.4.5 + 4.5.6.7-3.4.5.6+....+ 48.49.50.51--47.48.49.50
4F =48.49.50.51
F=(48.49.50.51)/4
đặt S=1.2.3+2.3.4+....+47.48.49
4S=1.2.3.(4-0)+2.3.4.(5-1)+...+47.48.49.(50-46)
4S=1.2.3.4-1.2.3+2.3.4.5-1.2.3.4+....+47.48.49.50-46.47.48.49
4S=47.48.49.50-1.2.3
S=(47.48.49.50-1.2.3):4
Mình nghĩ đề bài thế này mới đúng : 1.2.3+2.3.4+...+48.49.50
Đặt B = 1.2.3 + 2.3.4 + ....... + 48.49.50
B = 1.2.3 + 2.3.4 +....+ 48.49.50
\(\Rightarrow\)4B= 1.2.3.4 + 2.3.4.4 +.....+48.49.50.4
=1.2.3.4 + 2.3.4.(5-1) +.....+48.49.50.(51-47)
=1.2.3.4 + 2.3.4.5 - 1.2.3.4 +.....+ 48.49.50.51 - 47.48.49.50
=48.49.50.51
= 1499400
Vậy 1.2.3 + 2.3.4 + ....... + 48.49.50 = 1499400
Cảm ơn bạn