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a ) | x + 1/3 | = 5/6
+) x + 1/3 = 5/6 hay x + 1/3 = -5/6
x = 5/6 - 1/3 x = -5/6 - 1/3
x = 1/2 x =-7/6
b ) 11/13 - ( 5/42 - x ) = - ( 15/28-11/13 )
11/13 - ( 5/42 - x ) = 113/364
( 5/42 - x ) = 11/13 - 113/364
( 5/42 - x ) = 15/28
x = 5/42 - 15/28
x = -5/12
c ) | x |/186 = ( 1 - 303030 / 313131 ) + ( 616161 / 626262 - 1 )
| x | / 186 = 1/62
| x | = 1/62 . 186
| x | = 3
x = 3 hoặc -3
a) \(\frac{7}{4}x.\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)=32\)
\(\frac{7}{4}x.\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)=32\)
\(\frac{7}{4}x.\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}\right)=32\)
\(\frac{7}{4}x.33.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)=32\)
\(\frac{7}{4}x.33.\left(\frac{1}{3}-\frac{1}{7}\right)=32\)
\(\frac{7}{4}x.33\cdot\frac{4}{21}=32\)
đến đây thì bn tự lm đk r
b) \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+\frac{1}{15}+...+\frac{2}{x.\left(x-1\right)}=\frac{2007}{2009}\)
\(\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+\frac{2}{30}+...+\frac{2}{\left(x-1\right).x}=\frac{2007}{2009}\)
\(\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+\frac{2}{5.6}+...+\frac{2}{\left(x-1\right).x}=\frac{2007}{2009}\)
\(2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{x-1}-\frac{1}{x}\right)=\frac{2007}{2009}\)
\(2.\left(\frac{1}{2}-\frac{1}{x}\right)=\frac{2007}{2009}\)
\(1-\frac{2}{x}=\frac{2007}{2009}\)
\(\frac{2}{x}=\frac{2}{2009}\)
=> x = 2009
Kết quả : Viết lại biểu thức đã cho
=> -7/4x . ( 33/12 + 33/20 + 33/30 + 33/42 ) = 22
-7/4x . 33 . ( 1/12 + 1/20 + 1/30 + 1/42 ) = 22
-231/4x . ( 1/3 . 4 + 1/ 4. 5 + 1/5 . 6 + 1/ 6. 7 ) = 22
-231/4x . ( 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7 ) = 22
-231/4x . ( 1/3 - 1/7 ) = 22
-231/4x . 4/21 = 22
-11x = 22
x = 22 : -11
x = -2
Vậy x = -2