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a,35x34+35x86+65x75+65x45
=35x(34+86)+65x(75+45)
=35x120+65x120
=120x(35+65)
=120x100
=12000
b,3x25x8+4x37x6+2x38x12
=(3x8)x25+(4x6)x37+(2x12)x38
=24x25+24x37+24x38
=24x(25+37+38)
=24x(62+38)
=24x100
=2400
c,12x53+53x172-53x84
=53x(12+172-84)
=53x(184-84)
=53x100
=5300
a.35x(34+86)+65x(75+45)=35x120+65x120=120x(35+65)=120x100=12000
b.3x25x8+4x37x6x2x38x12=24x25+24x37+24x38=24x(25+37+38)=24x100=2400
c.53x(12+172-84)=53x100=5300
Ta có: \(A=1+\dfrac{1}{8}+\dfrac{1}{24}+\dfrac{1}{48}+\dfrac{1}{80}+\dfrac{1}{120}\)
\(\Leftrightarrow2A=2+\dfrac{2}{2\cdot4}+\dfrac{2}{4\cdot6}+\dfrac{2}{6\cdot8}+\dfrac{2}{8\cdot10}+\dfrac{2}{10\cdot12}\)
\(\Leftrightarrow2A=2+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{12}\)
\(\Leftrightarrow2A=2+\dfrac{1}{2}-\dfrac{1}{12}\)
\(\Leftrightarrow2A=\dfrac{24}{12}+\dfrac{6}{12}-\dfrac{1}{12}\)
\(\Leftrightarrow2A=\dfrac{29}{12}\)
hay \(A=\dfrac{29}{24}\)
a) \(1+2+3+...+2021=\dfrac{\left(2021+1\right)\left(\dfrac{2021-1}{1}+1\right)}{2}=2043231\)
b) Giống a
c) \(11+13+15+...131=\dfrac{\left(131+11\right)\left(\dfrac{131-11}{2}+1\right)}{2}=4331\)
a: \(2\cdot53\cdot12+4\cdot6\cdot87-3\cdot8\cdot40\)
\(=24\left(53+87-40\right)\)
=2400
b: \(5\cdot7\cdot77+7\cdot60+49\cdot25-45\cdot42\)
\(=35\cdot77+35\cdot12+49\cdot25-45\cdot42\)
\(=35\cdot89+35\left(7\cdot5-9\cdot6\right)\)
\(=35\cdot70=2450\)
a) 2.53.12+4.6.87-3.8.40
=24.53+24.87-24.40
=24.(53+87-40)
=24.100
=2400
b) 5.7.77-7.60+49.25-45.42
=5.7.77-7.60+7.7.25-45.6.7
=7.(5.77-60+7.25-6.45)
=7.230
=1610
Bài 2:
a: =>x-35=-23
=>x=12
b: =>|x-8|=13
=>x-8=13 hoặc x-8=-13
=>x=21 hoặc x=-5
Bài 1:
a: =42-98-42+12-12=-98
b: =10x4x3x(-25)=40x(-25)x3=-1000x3=-3000
a) 34 x 35 + 86 x 35 + 65 x 75 + 65 x 45
= ( 34 + 86 ) x 35 + 65 x ( 75 + 45 )
= 120 x 35 + 65 x 120
= 120 x ( 65 + 35 )
= 120 x 100
= 12000
b) ............
a, 34x35+86x35+65x75+65x45
=35x(34+86)+65x(75+45)
=35x120+65x120
=120x(35+65)
=120x100
=12000