Câu hỏi của Triều Nguyễn Quốc

Question

1. tim x

a: x : [(1800+600):30] = 560 : 1515 + 35

Kudo Shinichi · Accepted Answer

a) $x:\left[\left(1800+600\right):30\right]=560:1515+35$

$x:\left[\left(1800+600\right):30\right]=\dfrac{112}{303}+35$

$x:\left[\left(1800+600\right):30\right]=\dfrac{10717}{303}$

$x:\left[2400:30\right]=\dfrac{10717}{303}$

$x:80=\dfrac{10717}{303}$

$x=\dfrac{10717}{303}.80$

$x=\dfrac{857360}{303}$Câu trả lời: a) $x:\left[\left(1800+600\right):30\right]=560:1515+35$

$x:\left[\left(1800+600\right):30\right]=\dfrac{112}{303}+35$

$x:\left[\left(1800+600\right):30\right]=\dfrac{10717}{303}$

$x:\left[2400:30\right]=\dfrac{10717}{303}$

$x:80=\dfrac{10717}{303}$

$x=\dfrac{10717}{303}.80$

$x=\dfrac{857360}{303}$