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a) |2x-1|=|-7|
<=>|2x-1|=7
<=>\(\left[\begin{matrix}2x-1=7\\-\left(2x-1\right)=7\end{matrix}\right.\)
<=>\(\left[\begin{matrix}x=4\\x=-3\end{matrix}\right.\)
Vậy: x=-3 hoặc x=4
\(a,8x-75=5x+21\)
\(8x-5x=21+75\)
\(3x=96\)
\(x=32\)
\(b,9x+25=-\left(2x-58\right)\)
\(9x+25=-2x+58\)
\(9x+2x=58-25\)
\(11x=33\)
\(x=3\)
\(c,\left(5-x\right).\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5-x=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-2\end{cases}}}\)
a, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)
\(\Leftrightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}\Leftrightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)
b, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}\Leftrightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)
f, \(9x+25=-\left(2x-58\right)\Leftrightarrow9x+25=-2x+58\)
\(\Leftrightarrow11x-33=0\Leftrightarrow x=3\)
Làm nốt nhé !
a. \(\left|x-3\right|-16=-4\)
\(\Rightarrow\left|x-3\right|=12\)
\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)
b. \(26-\left|x+9\right|=-13\)
\(\Rightarrow\left|x+9\right|=39\)
\(\Rightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}\)
c. \(5-\left(10-x\right)=7\)
\(\Rightarrow10-x=-2\)
\(\Rightarrow x=12\)
d. \(11+\left(15-x\right)=1\)
\(\Rightarrow15-x=-10\)
\(\Rightarrow x=25\)
e. \(8x-75=5x+21\)
\(\Rightarrow8x-5x=75+21\)
\(\Rightarrow3x=96\)
\(\Rightarrow x=32\)
f. \(9x+25=-\left(2x-58\right)\)
\(\Rightarrow9x+25=-2x+58\)
\(\Rightarrow9x+2x=58-25\)
\(\Rightarrow11x=33\)
\(\Rightarrow x=3\)
g. \(\left|x+3\right|=4\)
\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=-4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=-7\end{cases}}\)
h. \(15-\left|2x-1\right|=\left|-8\right|\)
\(\Rightarrow15-\left|2x-1\right|=8\)
\(\Rightarrow\left|2x-1\right|=7\)
\(\Rightarrow\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)
a) 8x-75=5x+21
8x-5x=21+75
3x=96:3
x=32
b) 9x+25=-(2x-58)
9x+25=-2x+58
9x+2x=58-25
11x=33
x=33:11
x=3
tick mình nha
\(8x-75=5x+21\)
\(8x-5x=75+21\)
\(3x=96\)
\(x=32\)
Vậy \(x=32.\)
\(9x+25=-\left(2x-58\right)\)
\(9x+25=-2x+58\)
\(9x+2x=-25+58\)
\(11x=33\)
\(x=3\)
Vậy \(x=3.\)
\(15-\left|2x-1\right|=-8\)
\(\left|2x-1\right|=23\)
\(\Rightarrow\orbr{\begin{cases}2x-1=23\\2x-1=-23\end{cases}\Rightarrow}\orbr{\begin{cases}2x=24\\2x=-22\end{cases}}\Rightarrow\orbr{\begin{cases}x=12\\x=-11\end{cases}}\)
Vậy \(x\in\left\{12;-11\right\}\)
8x-5x=75+21
3x=96
x=32
9x+25=-2x+58
9x+2x=58-25
11x=33
x=3
Mình không viết lại đề nhé!
a) 27 - x + 15 + x = x + 2
-x + x - x = 2 - 15 - 27
-x = -40
x = 40
b) 8x - 75 = 5x +21
8x - 5x = 21 + 75
3x = 96
x = 32
c) 15 - |2x - 1| = |-8|
15 - 2x + 1 = 8
-2x = 8 -1 -15
-2x = -8
x = 4
d) 9x + 25 = -(2x - 58)
9x + 25 = -2x + 58
9x +2x = 58 - 25
7x = 33
x = 33/7
a ) | 2x - 1 | = | -7 |
| 2x - 1 | = 7
+ ) 2x - 1 = 7
2x = 8
x = 4
+ ) 2x - 1 = -7
2x = -6
x = -3
Vậy .........
b ) | x + 5 | = 0
x + 5 = 0
x = -5
Vậy ............
c ) 8x - 75 = 5x + 21
8x - 5x = 21 + 75
3x = 96
x = 32
Vậy .......
d ) 9x + 25 = -2x + 58
9x + 2x = 58 - 25
11x = 33
x = 3
Vậy ........
a, \(\left|2x-1\right|=\left|-7\right|\Rightarrow\left|2x-1\right|=7\)
\(\Rightarrow2x-1\in\left\{-7;7\right\}\)
+) \(2x-1=7\Rightarrow2x=7+1\)
\(\Rightarrow2x=8\Rightarrow x=8\div2=4\)
+) \(2x-1=-7\Rightarrow2x=-7+1\)
\(\Rightarrow2x=-6\Rightarrow x=-6\div2=-3\)
Vậy \(x\in\left\{-3;4\right\}\)
b, \(\left|x+5\right|=0\Rightarrow x+5=0\)
\(\Rightarrow x=0-5\Rightarrow x=-5\)
Vậy x = -5
c, \(8x-75=5x+21\Rightarrow8x-5x=21+75\)
\(\Rightarrow\left(8-5\right)x=96\Rightarrow3x=96\)
\(\Rightarrow x=96\div3\Rightarrow x=32\)
Vậy x = 32
d, \(9x+25=-\left(2x-58\right)\Rightarrow9x+25=-2x+58\)
\(\Rightarrow9x+2x=58-25\Rightarrow\left(9+2\right)x=33\)
\(\Rightarrow11x=33\Rightarrow x=33\div11\Rightarrow x=3\)
Vậy x = 3