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a,\(\dfrac{3.5.7.11.13.37-10101.55}{1212120+40404}\)
\(=\dfrac{55\left(3.7.13.37-10101\right)}{1212120+40404}\)
\(=\dfrac{55.0}{1212120+40404}=0\)
\(A=\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)
Tớ làm luôn
A=\(\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}\)
A=\(\frac{5}{9}\)
\(a,A=\dfrac{201220122012}{201320132013}=\dfrac{201220122012:100010001}{201320132013:100010001}=\dfrac{2012}{2013}\)
\(b,B=\dfrac{3.5.7.11.13.37-10101}{1212120+40404}=\dfrac{5.11.10101-10101}{10101.120+10101.4}=\dfrac{10101.\left(5.11-1\right)}{10101.\left(120+4\right)}=\dfrac{54}{124}=\dfrac{27}{62}\)
A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62
đúng nhé
\(\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{3.5.7.11.13.37-3.7.13.37}{40404.30+40404.1}\)
\(=\frac{3.7.13.37.\left(5.11-1\right)}{40404.\left(30+1\right)}\)
\(=\frac{3.7.13.37.54}{40404.31}\)
\(=\frac{3.7.13.37.54}{3.7.13.37.31.4}\)
\(=\frac{54}{31.4}=\frac{27}{62}\)
Ta có:
\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)
\(=\frac{\left(3.7.11.13.37\right).5-10101.1}{120.10101+4.10101}\)
\(=\frac{10101.\left(5-1\right)}{10101.\left(120+4\right)}\)
\(=\frac{4}{124}=\frac{1}{31}\)
Sai rồi:
A = 5.11.(3.7.13.37) - 10101/(10101.120 + 10101.4)
= (5.11.10101 - 10101)/(10101.120+10101.4)
= 10101(5.11-1)/10101(120+4)
= 27/62.
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5\cdot\left(1+11+111+1111\right)}{9\cdot\left(1+11+111+1111\right)}=\frac{5}{9}\)
a, \(\dfrac{3.5.7.11.13.37-10101.55}{1212120+40404}\)
\(=\dfrac{55\left(3.7.13.37-10101\right)}{1212120+40404}\)
\(=\dfrac{55.0}{1212120+40404}=0\)
b, \(\dfrac{5+55+555+5555}{9+99+999+9999}\)
\(=\dfrac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\dfrac{5}{9}\)
Chúc bạn học tốt!!!