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\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{3}{7}\)
= \(\frac{7}{5}-\frac{4}{5}:\frac{3}{7}\)
= \(\frac{7}{5}-\frac{28}{15}\)
= \(-\frac{7}{15}\)
\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{3}{7}\)
=>\(\frac{28}{15}\cdot\frac{3}{4}-\left(\frac{55}{100}+\frac{25}{100}\right)\cdot\frac{7}{3}\)
=>\(\frac{84}{60}-\frac{80}{100}\cdot\frac{7}{3}\)
=>\(\frac{7}{5}-\frac{4}{5}\cdot\frac{7}{3}=\frac{7}{5}-\frac{28}{15}\)
=>\(\frac{7}{5}-\frac{18}{14}=\frac{98}{60}-\frac{90}{60}=\frac{8}{60}=\frac{4}{30}\)
= 4/9 : -8 - (-1/4 + 9/20) : 14/5
= 4/9 : -8 - 1/5 : 14/5
= -1/18 - 1/5 : 14/5
= -1/18 - 1/14
= -8/63
\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right):\frac{7}{3}\)
\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{11}{20}+\frac{1}{4}\right):\frac{7}{3}\)
\(=\frac{7}{5}-\frac{4}{5}.\frac{3}{7}\)
\(=\frac{7}{5}-\frac{12}{35}\)
\(=\frac{37}{35}\)
Đặt A=\(1\frac{13}{15}\). \(0,75\) - (\(\frac{11}{20}\)+25%):\(\frac{7}{3}\)
A=\(\frac{28}{15}\). \(\frac{3}{4}\)-(\(\frac{11}{20}\)+\(\frac{1}{4}\)). \(\frac{3}{7}\)
A=\(\frac{7}{5}\)- \(\frac{4}{5}\).\(\frac{3}{7}\)
A=\(\frac{7}{5}\)-\(\frac{12}{35}\)
A=\(\frac{37}{35}\)
=28/15 . 3/4 - 4/5 : 7/5
= 7/5 - 4/5 x 5/7
= 7/5 - 4/7
= 49/35 - 20/35
= 29/35
`1 13/15 . 0,75 - (11/20 + 25%) : 1 2/5`
=` 28/15 . 3/4 - (11/20 + 1/4) . 75/7`
= `7/5 - 4/5 . 57 `
= `7/5 - 4/7`
= `29/35`
a:\(=5-\dfrac{7}{39}\cdot\dfrac{13}{7}+\dfrac{2}{9}=5-1+\dfrac{2}{9}=4+\dfrac{2}{9}=\dfrac{38}{9}\)
b: \(=\dfrac{28}{15}:\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{5}{20}\right)\cdot\dfrac{3}{7}\)
\(=\dfrac{112}{45}-\dfrac{4}{5}\cdot\dfrac{3}{7}\)
\(=\dfrac{112}{45}-\dfrac{12}{35}=\dfrac{676}{315}\)
= 28/15 . 3/4 - ( 11/20 + 1/4 ) : 7/3
= 28/15 . 3/4 - 4/5 : 7/3
= 7/5 - 12/35
= 37/35
= \(\dfrac{28}{15}\) . \(\dfrac{3}{4}\) - (\(\dfrac{11}{20}\) + \(\dfrac{1}{4}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - (\(\dfrac{11}{20}\) + \(\dfrac{5}{20}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) x \(\dfrac{3}{7}\)
= \(\dfrac{7}{5}\) - \(\dfrac{12}{35}\)
= \(\dfrac{49}{35}\) - \(\dfrac{12}{35}\)
= \(\dfrac{37}{35}\)
\(1\frac{13}{15}\) . 0,75 - ( 11/20 +25% ) :3/7
=\(\frac{28}{15}\) . 3/4 - ( 11/20 +25/100 ) :3/7
=28/15. 3/4- 4/5 : 3/7
=7/5 - 28/15
=-7/15
Thấy đúng thì bấm đúng cho mh nha!!!
\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)
\(=\frac{28}{15}.\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{29}{35}\)
\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)
\(=\frac{28}{15}\cdot\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{29}{35}\)