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B=1 x 2 + 2 x 3 + 3 x 4 + 4 x 5 +5 x 6 + ........... + 2015 x 2016
3xB=1 x 2x3 + 2 x 3x3 + 3 x 4x3 + 4 x 5x3 +5 x 6x3 + ........... + 2015 x 2016x3
=1x2x3+2x3x(4-1)+3x4x(5-2)+4x5x(6-3)+...+2014x2015(2016-2013)+2015x2016(2017-2014)
=1x2x3+2x3x4-1x2x3+3x4x5-2x3x4+4x5x6-3x4x5+..+2014x2015x2016-2013x2014x2015+2015x2016x2017-2014x2015x2016
các số hạng tự triệt tiêu nhau
còn lại (2015x2016x2017)
B= (2015x2016x2017)/3=2015x672x2017
2015=5.43
672=.3.4.7.8
=> B chia hết cho 2,4,6,7,8
không chia hết cho 9
1) 9 x 10 + 10 x 11 + 11 x 12 + ....+ 2015 x 2016
=9x10x11-8x9x10+10x11x12-9x10x11+...+2015x2016x2017-2014x2015x2013
=2015x2016x2017-8x9x10
=8193537360
( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 1 + 1/3 - 4/3)
=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x ( 4/3 - 4/3)
=( 2013 x 2014 + 2014 x 2015 + 2015 x 2016) x 0
=0
Ta có: \(\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(1+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
\(=\left(2013\cdot2014+2014\cdot2015+2015\cdot2016\right)\left(\dfrac{3}{3}+\dfrac{1}{3}-\dfrac{4}{3}\right)\)
=0
(1-1/2)x(1-1/3)x(1-1/4) x ...x (1-1/2016)
= 1/2x2/3x3/4x.....x2015/2016
= \(\frac{1x2x3x...x2015}{2x3x4x...x2016}\)
= 1/2016
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times...\times\left(1-\frac{1}{2016}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times...\times\frac{2015}{2016}\)
\(=\frac{1}{2016}\)
\(\frac{5932+6001x5931}{5932x6001-69}=\frac{6001x5931+5932}{5931x6001+6001-69}=\frac{6001x5931+5932}{6001x5931+5932}=1\)
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)..........\left(1-\frac{1}{2016}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.........\frac{2015}{2016}\)
\(=\frac{1.2.......2015}{2.3.......2016}\)
\(=\frac{1}{2016}\)
\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)........\left(1-\frac{1}{2016}\right)\)
\(=\frac{1}{2}.\frac{2}{3}.......\frac{2015}{2016}=\frac{1}{2016}\)
=1/2x2/3x/3/4/.................x2003/2004
= 1x2x3x................x2003
___________________
2x3x4x................x 2004
=1/2004
(1-1/2)x(1-1/3)x(1-1/4)x.....x(1-1/2015)x(1-1/2016)
=> 1/2 x 2/3 x 3/4 x 4/5 x 5/6 x 6/7 x 7/8 x 8/9 x......... x 2014/2015 x 2015/2016
Ta rút gọn cho tử này mẫu kia còn: 1/2016.
Đáp số : 1/2016
\(=\frac{2-1}{2}\times\frac{3-1}{3}\times\frac{4-1}{4}\times...\times\frac{2015-1}{2015}\times\frac{2016-1}{2016}\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times...\times\frac{2014}{2015}\times\frac{2015}{2016}\)
\(=\frac{1}{2016}\)