\(\left(2\sqrt{7}+4\sqrt{3}\right)\sqrt{3}-\sqrt{84}\)
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bài 1:
a: Ta có: \(2\sqrt{18}-9\sqrt{50}+3\sqrt{8}\)
\(=6\sqrt{2}-45\sqrt{2}+6\sqrt{2}\)
\(=-33\sqrt{2}\)
b: Ta có: \(\left(\sqrt{7}-\sqrt{3}\right)^2+7\sqrt{84}\)
\(=10-2\sqrt{21}+14\sqrt{21}\)
\(=12\sqrt{21}+10\)
Bài 2:
a: Ta có: \(\sqrt{\left(2x+3\right)^2}=8\)
\(\Leftrightarrow\left|2x+3\right|=8\)
\(\Leftrightarrow\left[{}\begin{matrix}2x+3=8\\2x+3=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{11}{2}\end{matrix}\right.\)
b: Ta có: \(\sqrt{9x}-7\sqrt{x}=8-6\sqrt{x}\)
\(\Leftrightarrow4\sqrt{x}=8\)
hay x=4
c: Ta có: \(\sqrt{9x-9}+1=13\)
\(\Leftrightarrow3\sqrt{x-1}=12\)
\(\Leftrightarrow x-1=16\)
hay x=17
2\(\left(\sqrt{28}-2\sqrt{3}+\sqrt{7}\right)\sqrt{7}+\sqrt{84}\)
= \(14-\sqrt{84}+7-\sqrt{84}\)
= 21
\(\left(\sqrt{28}-2\sqrt{3}+\sqrt{7}\right)\sqrt{7}+\sqrt{84}\)
\(=\sqrt{196}-\sqrt{84}+7+\sqrt{84}\)
\(=14+7=21\)
a) \(\sqrt{2}.\sqrt{98}=\sqrt{196}=14\)
b) \(\sqrt{75}:\sqrt{3}=\sqrt{25}=5\)
c) \(\sqrt{\left(3-\sqrt{11}\right)^2}=3-\sqrt{11}\)
d) \(\left(2\sqrt{7}+4\sqrt{3}\right).\sqrt{3}-\sqrt{84}=2\sqrt{21}+12-2\sqrt{21}=12\)
Nhớ tick
=\(2\sqrt{21}+12-2\sqrt{21}\)
=\(12\)