Tổng: 1+2+3+4+......+2010 có chia hết cho 5 ko? Vì sao???😭😭😭😭😭
Giúp hộ với ghi cả cách giải nha!!!!😗😗😗
Thank trước!!!😚😚
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3.52x-1=517.(13+62)
3.52x-1=517.75
52x-1 =517.75:3
52x-1 =517.25
52x-1 =517.52
52x-1 =519
2x-1 =19
2x =19+1
2x =20
x =20 :2
x = 10 Vậy x = 10
Complete each blank with one given word. There are more words than needed.
1. My mother got wet because she forgot her umbrella.
2. It's raining, so we cant play football un the stadium.
3. He is studying in a high school.
4. He will study there at the beginning of June 2011.
5. On the teacher's day we gave our teachers red roses which were very beautiful.
6. Many foreigners enjoy the festival in Ninh Binh Provice although Foreigner do not understand the people and the culture of Binh Dinh Provice very much.
Complete each blank with one given word. There are more words than needed.
1. My mother got wet because she forgot her umbrella.
2. It's raining, so we cant play football un the stadium.
3. He is studying in a high school.
4. He will study there at the beginning of June 2011.
5. On the teacher's day we gave our teachers red roses which were very beautiful.
6. Many foreigners enjoy the festival in Ninh Binh Provice even though Foreigner do not understand the people and the culture of Binh Dinh Provice very much.
( Mk cx thik đọc Conan nek ahihi )
\(M=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^5.2^7.3^7+2^7.2^3.3^{10}}\)
\(=\frac{2^{11}.3^6\left(2^2+3^3\right)}{2^{10}.3^7\left(2^2+3^3\right)}\)
\(=\frac{2}{3}\)
\(M=\frac{2.\left(2^3\right)^4.\left(3^3\right)^2+2^2.\left(2.3\right)^9}{2^5.\left(2.3\right)^7+2^7.2^3.\left(3^2\right)^5}\)
\(M=\frac{2.2^{12}.3^6+2^2.2^9.3^9}{2^5.2^7.3^7+2^7.2^3.3^{10}}\)
\(M=\frac{2^{13}.3^6+2^{11}.3^9}{2^{12}.3^7+2^{10}.3^{10}}\)
\(M=\frac{2^{11}.3^6\left(2^2.1+1.3^3\right)}{2^{10}.3^7\left(2^2.1+1.3^3\right)}\)
\(M=\frac{2.31}{3.31}\)
\(M=\frac{2}{3}\)
Study well
Đề bài mình nghĩ là đúng, còn về cách làm thì bạn theo công thức " số lớn nhất thỏa mãn trừ đi số nhỏ nhất thỏa mãn, rồi chia cho khoảng cách giữa các số rồi cộng 1"
Có bởi vì 2010 có tận cùng là số 0 nên chia hết cho 5
1 + 2 + 3 + ... + 2010 ( có 2010 số hạng )
= \(\frac{\left(2010+1\right).2010}{2}\)
= 2021055 chia hết cho 5