Tính tổng:
A=3+8+13+18+....+98
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\(a,=\dfrac{x^3+2x}{\left(x-1\right)\left(x^2+x+1\right)}+\dfrac{2}{x^2+x+1}-\dfrac{1}{x-1}=\dfrac{x^3+2x+2x-2-\left(x^2+x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^3+3x-3}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^3+3}{\left(x^2+x+1\right)}\)
a: \(=\dfrac{x^3+2x+2x-2-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(=\dfrac{x^3-x^2+3x-3}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^2+3}{x^2+x+1}\)
b: \(=\dfrac{x^2-2x-3+x^2+2x-3+2x-2x^2}{\left(x-3\right)\left(x+3\right)}\)
\(=\dfrac{2x-6}{\left(x-3\right)\left(x+3\right)}=\dfrac{2}{x+3}\)
c: \(=\dfrac{6-7+x}{3\left(x-1\right)}=\dfrac{x-1}{3\left(x-1\right)}=\dfrac{1}{3}\)
d: \(=\dfrac{x^3+2x+2x-2-x^2-x-1}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^3-x^2+3x-3}{\left(x-1\right)\left(x^2+x+1\right)}=\dfrac{x^2+3}{x^2+x+1}\)
\(c,\Leftrightarrow3x-5-x-7=2\Leftrightarrow2x-12=2\Leftrightarrow2x=14\Leftrightarrow x=7\)
\(d,\left\{{}\begin{matrix}x=6\\y-1=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=6\\y=7\end{matrix}\right.\)
Câu C:
(3x−5)−(x+7)=2
3x−5−x−7=2
2x−5−7=2
2x−12=2
2x=2+12
2x=14
x=214
x=7
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dẫy số trên có số số hạng là : ( 98 - 3 ) : 5 + 1 = 20
Tổng dãy số trên là :( 98 + 3 ) x 20 : 2 = 1010
ok mik giúp
nhận xét 8-3=5
13-8=5
.....
đây là dãy số cách đều 5 đôn vị
số các số hạng là
(98-3):5+1=20 số
tổng là
(98+3)*20:2=1010
đáp số...
nha đúng 100%