Tìm 1 số tự nhiên biết rằng nếu chia số đó cho 24 hoặc 26 đều dư 5 và có thương hơn kém nhau 2 đơn vị
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17 tháng 2 2016
Từ đề bài ta có được các đẳng thức sau
x=24.r1+5
x=26.r2+5
r1-r2=2=>r1=r2+2
thay vào biểu thức đầu ta được
x=24.(r2+2)+5=24r2+48+5=24r2+53
=>2r2-48=0
r2=24
x=24.24+5=581
2 tháng 3 2016
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TG
26 tháng 10 2016
4 là số dư lớn nhất trong phép chia cho 5
Gọi số cần tìm là a và b = a + 16
b chia hết cho 5 và thương tăng thêm 4
b chia hết cho 9 và thương tăng thêm 2
Lúc này 2 thương hơn kém nhau 26 + 2 = 28
9 x 5 = 45 nên 45 chia cho 9 bằng 5 và 45 chia cho 5 bằng 9
Số b là : 45 x 28 : (9 - 5) = 315
Số cần tìm là : 315 - 16 = 299
LN
13 tháng 3 2016
Gọi n là thương của phép chia cho 26, ta được:
26 x n + 5 = 24 x (n+2) + 5 = 24 x n + 48 + 5
2 x n = 48
n = 48 : 2 = 24
Số cần tìm là:
26 x 24 + 5 = 629
Đáp số:629
Ai tích mình mình tích lại cho(đi mà)
Gọi số cần tìm la x: thuong cua x chia cho 26 la a thi x chia cho 24 duoc thuong la x+2.
Theo bài ra ta có: x:26=a dư 5 \(\Rightarrow\)x= 26a+5 (1)
x:24=a+2 du 5 \(\Rightarrow\)x= 24(a+2) + 5
suy ra: 26a+5 = 24(a+2)+5
\(\Rightarrow\)26a = 24a + 48
\(\Rightarrow\)26a - 24a = 48
\(\Rightarrow\)2a = 48
\(\Rightarrow\)a = 48 : 24 = 2
Thay a= 2 vao (1) ta duoc: x= 26*2 +5 = 57
Vay so can tim la 57
48 ở đâu vậy Đường Quỳnh Giang