Tính A= \(\frac{64^{20}.81^{15}.125^4}{128^{10}.729^5.625^2}\)
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1.
a) 1 + 2 + 3 + ... + x = 55
\(\Rightarrow\) x(1 + x) : 2 = 55
\(\Rightarrow\) x(1 + x) = 110
\(\Rightarrow\) x(1 + x) = 10(10 + 1)
\(\Rightarrow\) x = 10
a) = \(\frac{127}{96}\)
b) = \(\frac{255}{256}\)
c) Mik bỏ nha
d) = \(\frac{1023}{512}\)
e) = \(\frac{2343}{625}\)
Bài 1: 1/3+1/9+1/27+1/81+1/243+1/729
Đặt:
A = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
Nhân A với 3 ta có:
\(Ax3=3+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\)
\(\Rightarrow Ax3-S=3-\frac{1}{243}\)
\(\Rightarrow2A=\frac{2186}{729}\)
\(\Rightarrow A=\frac{2186}{729}:2\)
\(\Rightarrow A=\frac{1093}{729}\)
a) A= 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
A = 1 - 1/2 + 1/2- 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128 + 1/128 - 1/256 - 1/256 - 1/512
A = 1 - 1/512
A = 511/512
b) B = 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
3B = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243
3B - B = 1 - 1/729
2B = 728/729
B = 364/729
a) A= 1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
A = 1 - 1/2 + 1/2- 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 - 1/32 + 1/32 - 1/64 + 1/64 - 1/128 + 1/128 - 1/256 - 1/256 - 1/512
A = 1 - 1/512
A = 511/512
b) B = 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
3B = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243
3B - B = 1 - 1/729
2B = 728/729
B = 364/729
\(A=\frac{64^{20}.81^{15}.125^4}{128^{10}.729^5.625^2}\)
\(A=\frac{\left(2^6\right)^{20}.\left(3^4\right)^{15}.\left(5^3\right)^4}{\left(2^7\right)^{10}.\left(3^6\right)^5.\left(5^4\right)^2}\)
\(A=\frac{2^{120}.3^{60}.5^{12}}{2^{70}.3^{30}.5^8}\)
\(A=2^{50}.3^{30}.5^4\)
A = \(\frac{128^{10}.3^{60}.5^{12}}{128^{10}.3^{30}.5^8}=3^{30}.5^4\)