the value of 2/1x3 + 2/3x5+2/5x7+...+2/77x79 is
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Dấu : \("."\)là dấu nhân nhé
\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{77.79}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{77}-\frac{1}{79}\)
\(=1-\frac{1}{79}\)
\(=\frac{79}{79}-\frac{1}{79}\)
\(=\frac{78}{79}\)
Chúc bạn học tốt !!!
2/1.3 + 2/3.5 + 2/5.7 + ... + 2/2009.2011
= 1 - 1/3 + 1/3 - 1/5 + 1/5 - 1/7 + ... + 1/2009 - 1/2011
= 1 - 1/2011
= 2010/2011
Ta có : \(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+.....+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+......+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}\)
\(=\frac{100}{101}\)
Đặt : \(A=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{99\cdot101}\)
\(A-\frac{2}{1\cdot3}=\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{99\cdot101}\)
\(2A-\frac{2}{1\cdot3}=\frac{2}{3}-\frac{2}{5}+\frac{2}{5}-\frac{2}{7}+\frac{2}{7}-...+\frac{2}{99}-\frac{2}{101}\)
\(2A-\frac{2}{3}=\frac{2}{3}-\frac{2}{101}\)
\(2A-\frac{2}{3}=\frac{196}{303}\)
\(A-\frac{2}{3}=\frac{98}{303}\)
\(A=\frac{98}{303}+\frac{2}{3}=\frac{100}{101}\)
A = 2/1x3 + 2/3x5 + 2/5x7 + ... + 2/99x101
A = 2/1 - 2/101 = 200/101
Kết quả là 200/101 bạn nhé
2/2 + 1x3 / 3x5 + 2/2 + ······ + 5x7 / 97x99 + 2 / 99x101
= 1-1 / 3 + 1 / 3-1 / 5 + 1 / 5-1 / 7 + ... ... + 1 / 97-1 / 99 + 1 / 99-1 / 101
= 1-1 / 101
= 100/101
Đặt A =2/1x3+2\3x5+................+2/41x43
A =1/1-1/3+1/3-1/5+...................+1/41-1/43
A=1-1/43
A=42/43
\(\frac{2}{1x3}+\frac{2}{3x5}+\frac{2}{5x7}+....+\frac{2}{59x61}\)
\(=\frac{2}{2}x\left(\frac{2}{1x3}+\frac{2}{3x5}+\frac{2}{5x7}+.....+\frac{2}{59x61}\right)\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{59}-\frac{1}{61}\)
\(=1-\frac{1}{61}=\frac{60}{61}\)
\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{77.79}\)
=\(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{77}-\frac{1}{79}\)
=\(1-\frac{1}{79}\)
=\(\frac{78}{79}\)
Giá trị của 2 / 1x3 + 2 / 3x5 + 2 / 5x7 + ... + 2 / 77x79 là..........