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\(=\left(-2-\dfrac{7}{12}\right):\dfrac{15}{7}-\dfrac{1}{18}:\dfrac{15}{7}+\dfrac{20}{9}:\dfrac{15}{7}\)

\(=\dfrac{7}{15}\left(-2-\dfrac{7}{12}-\dfrac{1}{18}+\dfrac{20}{9}\right)\)

\(=\dfrac{7}{15}\cdot\dfrac{-72-21-2+80}{36}=\dfrac{7}{15}\cdot\dfrac{-15}{36}=\dfrac{-7}{36}\)

30 tháng 6 2023

\(\left(-2\dfrac{7}{12}\right):2\dfrac{1}{7}-\dfrac{1}{18}:2\dfrac{1}{7}+2\dfrac{2}{9}:2\dfrac{1}{7}\)

\(=\left(-2\dfrac{7}{12}-\dfrac{1}{18}+2\dfrac{2}{9}\right):2\dfrac{1}{7}\)

\(=\left(\dfrac{-31}{12}-\dfrac{1}{18}+\dfrac{20}{9}\right):2\dfrac{1}{7}\)

\(=-\dfrac{5}{12}:\dfrac{15}{7}\)

\(=-\dfrac{5}{12}\cdot\dfrac{7}{15}\)

\(=-\dfrac{7}{36}\)

c: \(=\dfrac{4}{9}\left(\dfrac{5}{7}+\dfrac{2}{5}+\dfrac{2}{7}-\dfrac{7}{5}\right)=\dfrac{4}{9}\cdot\left(1-1\right)=0\)

d: \(=\dfrac{4-3-1}{12}\cdot\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)=0\cdot\left(\dfrac{67}{111}+\dfrac{2}{33}-\dfrac{15}{117}\right)=0\)

8 tháng 4 2023

1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)

\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)

\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)

\(=\dfrac{40+\left(-135\right)+30}{180}\)

\(=\dfrac{-65}{180}\)

\(=\dfrac{-13}{36}\)

2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)

\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)

\(=\dfrac{-21}{36}-\dfrac{22}{36}\)

\(=\dfrac{-21-22}{36}\)

\(=\dfrac{-43}{36}\)

3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)

\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)

\(=\dfrac{14}{16}-\dfrac{-5}{16}\)

\(=\dfrac{14-\left(-5\right)}{16}\)

\(=\dfrac{19}{16}\)

4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)

\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)

\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)

\(=\dfrac{30-\left(-72\right)-25}{80}\)

\(=\dfrac{77}{80}\)

 

 

8 tháng 4 2023

1)` 2/9 + -3/4 + 5/30= (40+(-135) + 30 )/180 = -65/180 = -13/36`

 

2) `-7/12 - 11/18=(-21)/36 - 22/36 = -43/36 `

 

3) `7/8 - (-5)/16=14/16- (-5)/16 = 19/16 `

 

4) `3/8 - (-9)/10 - 5/16= (30- (-72) -25)/80=77/80`

7 tháng 6 2017

( 2 x y + 2/15 ) x 3 = 4/5

( 2 x y + 2/15 )      = 4/5 : 3 

( 2 x y + 2/15 )      =   4/15

 2 x y                    = 4/15 - 2/15 

2 x y                     =     2/15

     y                      =     2/15 :2 

   y                          =    1/15

7 tháng 6 2017

(2 x y + 2/15) x 3 = 4/5 

2 x y + 2/15) = 4/5 : 3 

2 x y + 2/15 = 4/15 

2 x y = 4/15 - 2/15 

2 x y = 2/15 

y = 2/15 : 2 

y = 1/15 

7/9 x (2 - 1/3 x y) = 14/15 

(2 - 1/3 x y) = 14/15 : 7/9 

(2 - 1/3 x y) = 6/5 

2 - y = 6/5 x 1/3 

2 - y = 2/5 

y = 2/5 + 2 

y = 12/5 

4/21 + 5 x y - 8/7 = 1/3 

4/21 + 5 x y = 1/3 + 8/7 

4/21 + 5 x y = 31/21 

5 x y = 31/21 - 4/21 

5 x y = 9/7 

y = 9/7 : 5 

y = 9/35 

7/12 x y - 3/12 x y = 5 

y x (7/12 - 3/12) = 5 

y x 1/3 = 5 

y = 5 : 1/3 

y = 15 

22 tháng 9 2019

1)

a) \(-\frac{9}{34}:\frac{17}{4}\)

\(=-\frac{18}{289}.\)

b) \(1\frac{1}{2}.\frac{1}{24}\)

\(=\frac{3}{2}.\frac{1}{24}\)

\(=\frac{1}{16}.\)

c) \(-\frac{5}{2}:\frac{3}{4}\)

\(=-\frac{10}{3}.\)

d) \(4\frac{1}{5}:\left(-2\frac{4}{5}\right)\)

\(=\frac{21}{5}:\left(-\frac{14}{5}\right)\)

\(=-\frac{3}{2}.\)

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22 tháng 9 2019

Viết phân số ở đâu vậy ạ?

8 tháng 8 2020

Bài 1 :

\(a)\frac{-17}{30}-\frac{11}{-15}+\left(-\frac{7}{12}\right)\)

\(=\frac{1}{6}+\left(-\frac{7}{12}\right)\)

\(=-\frac{5}{12}\)

\(b)-\frac{5}{9}+\frac{5}{9}:\left(1\frac{2}{3}-2\frac{1}{12}\right)\)

\(=-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)

\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)

\(=-\frac{5}{9}+\left(-\frac{2}{3}\right)\)

\(=-\frac{1}{9}\)

\(c)-\frac{7}{25}\times\frac{11}{13}+\left(-\frac{7}{25}\right)\times\frac{2}{13}-\frac{18}{25}\)

\(=-\frac{77}{325}+\left(-\frac{14}{325}\right)-\frac{18}{25}\)

\(=-\frac{7}{25}-\frac{18}{25}\)

\(=-1\)

28 tháng 6 2023

\(\left(-12\cdot\dfrac{2}{7}+\dfrac{8}{9}:3\dfrac{1}{2}-\dfrac{2}{7}\cdot\dfrac{5}{18}\right)\cdot3\dfrac{1}{2}\)

\(=\left(-12\cdot\dfrac{2}{7}+\dfrac{8}{9}\cdot\dfrac{2}{7}-\dfrac{2}{7}\cdot\dfrac{5}{18}\right)\cdot\dfrac{7}{2}\)

\(=\left(-12+\dfrac{8}{9}-\dfrac{5}{18}\right)\cdot\dfrac{2}{7}\cdot\dfrac{7}{2}\)

\(=-\dfrac{205}{18}\cdot1\)

\(=-\dfrac{205}{18}\)