Tìm x
A x-56 x 24 = 286
B 65 x 54- x = 1026
C 36 x 84 : x= 72
X : 47 = 326 - 277
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1:
a. A = 125 . (-61) . (-2)3 . (-1)24
= 125. (-8). (-61) . 124
= 125. 8. 61.1
= 1000. 61 = 61000
b. B = 136. (-47) + 36.47
= (-136).47 + 36.47
= 47. (-136 + 36)
= 47. (-100) = -4700
c. C = (-48).72 + 36.(-304)
= (-96).36 + 36. (-304)
= 36. (-96-304)
= 36. (-400) = -14400
d. D = 87.(13-18) - 13.(87 + 18)
= 87.13 - 87.18 - 13.87 - 13.18
= - 87.18 - 18.13
= - 18.(87+13)
= - 18.100 = -1800
Bài 2:
a. TH1: x - 2 = 0 => x = 2
TH2: 5-x = 0 => x = 5
b. |x| = 56 - 23 = 33 => x = cộng trừ 33
c. 3 - (17-x) = 289 - (36 + 289)
=> 3 - 17 + x = 289 - 289 - 36
=> -14 + x = -36
=> x = -36 - (-14) = -22
1.
a. A = 125 . (-61) . (-2)3 . (-1)24
= 125.(-61).(-8).1
= (-8.125).(-61)
= -1000.(-61)
= 61000
b. B = 136 . (-47) + 36 . 47
=-136.47+36.47
=47(-136+36)
= 47.(-100)
= -4700
2.
a. (x - 2) . (5 - x) = 0
=> x - 2 = 0 hoặc 5 - x = 0
=> x = 2 hoặc x = 5
b. 56 - lxl = 23
=> |x| = 33
=> x = 33 hoặc x = -33
c. 3 - (17 - x) = 289 - (36 + 289)
=> 3 - 17 + x = 289 - 36 - 289
=> -14 + x = -36
=> x = -22
Ta có: \(13\cdot\left(-47\right)-53\cdot13\)
\(=13\cdot\left(-47-53\right)\)
\(=13\cdot\left(-100\right)=-1300\)
Ta có: \(27\cdot\left(-67\right)+33\cdot\left(-27\right)\)
\(=27\cdot\left(-67\right)-33\cdot27\)
\(=27\left(-67-33\right)\)
\(=27\cdot\left(-100\right)=-2700\)
Ta có: \(-49\cdot65+36\cdot\left(-49\right)+49\)
\(=-49\cdot65+\left(-49\right)\cdot36+\left(-49\right)\cdot\left(-1\right)\)
\(=-49\cdot\left(65+36-1\right)\)
\(=-49\cdot100=-4900\)
Ta có: \(136\cdot\left(-47\right)+36\cdot47\)
\(=\left(-136\right)\cdot47+36\cdot47\)
\(=47\cdot\left(-136+36\right)\)
\(=47\cdot\left(-100\right)=-4700\)
Ta có: \(\left(-48\right)\cdot72+36\cdot\left(-304\right)\)
\(=-96\cdot36+36\cdot\left(-304\right)\)
\(=36\cdot\left(-96-304\right)\)
\(=36\cdot\left(-400\right)=-14400\)
tìm số tự nhiên x lớn nhất biết
a, 24 : x , 36 : x
b , 32 : x , 48 : x
c , 24 : x , 84 : x , 180 : x
a) 24 = 23 . 3
36 = 22 . 33
ƯCLN(24,36) = 22 . 3 = 4 . 3 = 12
b) 32 = 25
48 = 24 . 3
ƯCLN(32,48) = 24 = 16
c) 24 = 23 . 3
84 = 22 . 3 . 7
180 = 22 . 32 . 5
ƯCLN(24,84,180) = 22 . 3 = 4 . 3 = 12
a)\(2.x-138=8.9\)
\(2.x-138=72\)
\(2.x=72+138\)
\(2.x=210\)
\(x=210\div2\)
\(x=105\)
b)\(\left\{\left(6x-72\right)\div2-84\right\}.28=5628\)
\(\left(6x-72\right)\div2-84=201\)
\(\left(6x-72\right)\div2=285\)
\(6x-72=570\)
\(6x=642\)
\(x=107\)
c)\(420+65.4=\left(x+175\right)\div5+30\)
\(420+260=\left(x+175\right)\div5+30\)
\(680=\left(x+175\right)\div5+30\)
\(650=\left(x+175\right)\div5\)
\(3250=x+175\)
\(3075=x\)
a, (x + 30) – 75 = 125
=> x + 30 = 125 + 75 = 200
=> x = 200 – 30
=> x = 170
Vậy x = 170
b, x – 72 : 36 = 18
=> x – 2 = 18
=> x = 18 + 2 = 20
Vậy x = 20
c, x – 17 = 54
=> x = 54 +17
=> x = 71.
Vậy x = 71
d, 36 – (x – 2) = 12
=> x – 2 = 36 – 12
=> x = 24 + 2 = 26
Vậy x = 26
e, 9x – 7 = 837
=>9x = 837 + 7 = 844
=> x = 844 9
Vậy x = 844 9
f, (x – 15) – 107 = 0
=> x – 15 = 107
=> x = 107 +15
=> x = 122.
Vậy x = 122
g, 134 + (116 – x) = 145
=> 116 – x = 145 – 134
=> x = 116 – 11
=> x = 5.
Vậy x = 5
`@` `\text {Ans}`
`\downarrow`
`A.`
`x-56 \times 24 = 286`
`x-1344 = 286`
`x=286 + 1344`
`x=1630`
`B.`
`65 \times 54 - x = 1026`
`3510 - x =1026`
`x=3510 - 1026`
`x=2484`
`C.`
`36 \times 84 \div x = 72`
`3024 \div x = 72`
`x=3024 \div 72`
`x=42`
`D.`
`x \div 47 = 326 - 277`
`x \div 47 = 49`
`x= 49 \times 47`
`x=2303`
A. \(x-56\times24=286\\ x-1344=286\\ x=286+1344\\ x=1630\)
B. \(65\times54-x=1026\\ 3510-x=1026\\ x=3510-1026\\ x=2484\)
C. \(36\times84\div x=72\\ 3024\div x=72\\ x-3024\div72\\ x=42\)
D. \(x\div47=326-277\\ x\div47=49\\ x=49\times47\\ x=2303\)