12 - 12\(\dfrac{1}{3}\) = ?
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24 tháng 7 2021
\(A=\dfrac{636363\cdot37-373737\cdot63}{1+2+3+...+2006}\)
\(=\dfrac{37^2\cdot3^3\cdot7^2\cdot13-37^2\cdot3^3\cdot7^2\cdot13}{\left(2006+1\right)\cdot1003}\)
=0
11 tháng 8 2021
1: Ta có: \(\dfrac{x+4}{4}+\dfrac{3x-7}{5}=\dfrac{7x+2}{20}\)
\(\Leftrightarrow5x+20+12x-28=7x+2\)
\(\Leftrightarrow17x-7x=2+8=10\)
hay x=1
2: Ta có: \(\dfrac{x}{6}+\dfrac{1-3x}{9}=\dfrac{-x+1}{12}\)
\(\Leftrightarrow\dfrac{6x}{36}+\dfrac{4\left(1-3x\right)}{36}=\dfrac{3\left(-x+1\right)}{36}\)
\(\Leftrightarrow6x+4-12x=-3x+3\)
\(\Leftrightarrow-6x+3x=3-4\)
hay \(x=\dfrac{1}{3}\)
3: Ta có: \(\dfrac{x-3}{3}-\dfrac{x+2}{12}=\dfrac{2x-1}{4}\)
\(\Leftrightarrow4x-12-x-2=6x-3\)
\(\Leftrightarrow3x-14-6x+3=0\)
\(\Leftrightarrow-3x=11\)
hay \(x=-\dfrac{11}{3}\)
11 tháng 8 2021
4: Ta có: \(\dfrac{x-2}{4}-\dfrac{2x+3}{3}=\dfrac{x+6}{12}\)
\(\Leftrightarrow3x-6-8x-12=x+6\)
\(\Leftrightarrow-5x-x=6+18\)
hay x=-4
5: Ta có: \(\dfrac{2x-1}{12}-\dfrac{3-x}{18}=\dfrac{-1}{36}\)
\(\Leftrightarrow6x-3+2x-6=-1\)
\(\Leftrightarrow8x=8\)
hay x=1
AH
2
L
9 tháng 5 2022
\(\dfrac{1}{-12}+\dfrac{3}{4}+\dfrac{-1}{12}-\dfrac{1}{3}=\dfrac{-1}{12}+\dfrac{3}{4}+\dfrac{-1}{12}-\dfrac{1}{3}=\dfrac{-1}{12}+\dfrac{9}{12}+\dfrac{-1}{12}-\dfrac{4}{12}=\dfrac{\text{3}}{12}=\dfrac{1}{4}\)
14 tháng 4 2017
\(-1\dfrac{1}{5}.\dfrac{12+\dfrac{4}{3}-\dfrac{12}{37}-\dfrac{12}{35}}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}}:\dfrac{4+\dfrac{4}{17}+\dfrac{4}{19}+\dfrac{4}{2003}}{5+\dfrac{5}{17}+\dfrac{5}{19}+\dfrac{5}{2003}}\)
\(=\dfrac{-6}{5}.\dfrac{4\left(3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}\right)}{3+\dfrac{1}{3}-\dfrac{3}{37}-\dfrac{3}{35}}:\dfrac{4\left(1+\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{2003}\right)}{5\left(1+\dfrac{1}{17}+\dfrac{1}{19}+\dfrac{1}{2003}\right)}\)
\(=\dfrac{-6}{5}.4:\dfrac{4}{5}\)
\(=\dfrac{-6.4.5}{5.4}=-6\)
GA
1
11 tháng 6 2022
\(=\left(\dfrac{1}{12}+\dfrac{11}{12}\right)+\left(\dfrac{1}{5}-\dfrac{6}{5}\right)+\dfrac{1}{71}=1-1+\dfrac{1}{71}=\dfrac{1}{71}\)
LN
1
4 tháng 5 2022
\(\left(2\dfrac{7}{12}+4\dfrac{1}{3}\right)+3\dfrac{1}{12}\)
\(=2\dfrac{7}{12}+4\dfrac{1}{3}+3\dfrac{1}{12}\)
\(=\left(2\dfrac{7}{12}+3\dfrac{1}{12}\right)+4\dfrac{1}{3}\)
\(=\dfrac{17}{3}+\dfrac{13}{3}\)
\(=\dfrac{30}{3}=10\)
\(12-12\dfrac{1}{3}=12-\dfrac{12\times3+1}{3}=12-\dfrac{37}{3}=\dfrac{12\times3-37}{3}=\dfrac{36-37}{3}=\dfrac{-1}{3}\)
= 12 và 2/3\(\dfrac{ }{ }\)