1,5x2,9+0,5x21+1/100x12-2 trình bày ra nhé
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\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}\)
=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)
=\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3.}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)
=\(\frac{1}{1}-\frac{1}{10}\)
=\(\frac{9}{10}\)
1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90
= 1 / 1.2 + 1 / 2.3 + ` 1 / 3. 4 + 1 / 4 .5 + 1/5 .6 + 1/6 . 7 + 1 / 7.8 + 1 / 8.9 + 1 /9.10
= 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + .... + 1/8 - 1/9 + 1/9 - 1/10
= 1/1 - 1/10
= 9/10
\(B=\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2003}\right).\left(1-\frac{1}{2004}\right)\)
\(B=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{2002}{2003}.\frac{2003}{2004}\)
\(B=\frac{1.2.3.....2002.2003}{2.3.4.....2003.2004}\)
\(B=\frac{1}{2004}\)
B = (1 - 1/2).(1 - 1/3).(1 - 1/4).(1 - 1/5)...(1 - 1/2003).(1 - 1/2004)
B = 1/2 . 2/3 . 3/4 . 4/5 .... 2002/2003 . 2003/2004
B = 1.2.3.4...2002.2003/2.3.4.5...2003.2004
B = 1/2004
https://olm.vn/hoi-dap/detail/7709875367.html
(x+1).(x+2)=0
\(\hept{\begin{cases}x+1=0\\x+2=0\end{cases}}=\hept{\begin{cases}x=\left(-1\right)\\x=\left(-2\right)\end{cases}}\)
Vậy x= (-1) hoặc x = (-2)
mk làm đúng không bạn???
= 1,5 x 2,9 + 0,5 x 21 + 0,01 x 12 - 2
= 4,35 + 10,5 + 0,12 - 2
= 12,97