1. Tính các tổng sau:
a) D= 6/15x18 + 6/18x21 + 6/21x24 + .......... + 6/89x90
b) F= 1/25x27 + 1/27x29 + 1/29x31 + .............+1/73x75
^^^^^^^^^ Các bạn cố gắng giúp mình nha!!!!!!
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a) A = 9/8.11 + 9/11.14 + 9/14.17 + ... + 9/73.75
A = 3.(1/8 - 1/11 + 1/11 - 1/14 + 1/14 - 1/17 + ... + 1/73 - 1/75)
A = 3.(1/8 - 1/75)
A = 3.67/600
A = 67/200
Các bài sau làm tương tự, riêng câu D thì phân tích ra
Mình chỉ làm hộ bạn câu a) thôi nhé vì đề sàn sàn giống nhau :
a) \(A=\frac{9}{8×11}+\frac{9}{11×14}+\frac{9}{14×17}+...+\frac{9}{73×75}\)
\(A=\frac{9}{8}-\frac{9}{11}+\frac{9}{11}-\frac{9}{14}+\frac{9}{14}-\frac{9}{17}+...+\frac{9}{73}-\frac{9}{75}\)
\(A=\frac{9}{8}-\frac{9}{75}\)
\(A=\frac{675}{600}-\frac{72}{600}\)
\(A=\frac{673}{600}\)
Vậy,...
Cbht
b. B= 1/25×27+1/27×29+1/29×31+...+1/73×75
2B= 2.(1/25×27+1/27×29+1/29×31+...+1/73×75)
2B= 2/25×27+2/27×29+2/29×31+...+2/73×75
2B= 1/25-1/27+1/27-1/29+...+1/73-1/75
2B= 1/25-1/75
B=(1/25-1/75):2
Từng đó đã nha để mik nghĩ tiếp
T.i.c.k đc ko PLEASE!!!
\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+...+\frac{1}{73.75}\)
\(B=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\cdot\frac{2}{75}\)
\(B=\frac{1}{75}\)
\(B=\frac{1}{25.27}+\frac{1}{27.29}+\frac{1}{29.31}+....+\frac{1}{73.75}\)
\(B=\frac{1}{2}.\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\cdot\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\cdot\frac{2}{75}=\frac{1}{75}\)
bạn sai ở đoạn cuối
A=\(\frac{3\cdot3}{15\cdot18}+\frac{3\cdot3}{18\cdot21}+...+\frac{3\cdot3}{96\cdot99}=3\cdot\left(\frac{3}{15\cdot18}+\frac{3}{18\cdot21}+...+\frac{3}{96\cdot99}\right)=3\cdot\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+...+\frac{1}{96}-\frac{1}{99}\right)=3\cdot\left(\frac{1}{15}-\frac{1}{99}\right)=3\cdot\frac{28}{495}=\frac{28}{165}\)
\(\left(\frac{1}{25x27}+\frac{1}{27x29}+\frac{1}{29x31}+....+\frac{1}{73x75}\right)x\frac{3}{10}=x\)
\(< =>\frac{1}{2}x\left(\frac{2}{25x27}+\frac{2}{27x29}+\frac{2}{29x31}+....+\frac{2}{73x75}\right)x\frac{3}{10}=x\)
\(< =>\frac{1}{2}x\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+....+\frac{1}{73}-\frac{1}{75}\right)x\frac{3}{10}=x\)
\(< =>\frac{1}{2}x\left(\frac{1}{25}-\frac{1}{75}\right)x\frac{3}{10}=x< =>\frac{1}{2}x\frac{2}{25}x\frac{3}{10}=x< =>x=\frac{3}{250}\)
B8 = 6/15.18 + 6/18.21 + 6/21.24 + ... + 6/87.90
B8 = 2.(3/15.18 + 3/18.21 + 3/21.24 + ... + 3/87 .90)
B8 = 2.(1/15 - 1/18 + 1/18 -1/21 + 1/21 - 1/24 + ... + 1/87 - 1/90)
B8 = 2.(1/15 - 1/90)
B8 = 2.(6/90 - 1/90)
B8 = 2. 1/18
B8 = 1/9
B = 1/9 : 8
B = 1/72
D=6/15.18+6/18.21+...+6/89.92
D=6(1/15.18+1/18.21+...+1/89.92)
a) 3D=6(1/15-1/18+1/18-1/21+...+1/89-1/92)
3D=6(1/15-1/92)
3D=6.(77/1380)
3D=77/230
D=77/690
b) F=1/25.27+1/27.29+...+1/73.75
2F=2/25.27+2/27.29+..+2/73.75
2F=1/25-1/27+1/27-1/29+...+1/73-1/75
2F=1/25-1/75
2F=2/75
F=1/75