\(\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{1}{3}\)
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18 tháng 12 2021
Câu 1:
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{2}{3}\\x+\dfrac{1}{3}=-\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-1\end{matrix}\right.\)
18 tháng 12 2021
\(1,\Leftrightarrow\left(x+\dfrac{1}{3}\right)^2=\dfrac{4}{9}\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=\dfrac{2}{3}\\x+\dfrac{1}{3}=-\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=-1\end{matrix}\right.\\ 2,=15:\left(\dfrac{2}{3}\right)^4\cdot\left(\dfrac{2}{3}\right)^6:\left(\dfrac{2}{3}\right)^9=15\cdot\left(\dfrac{2}{3}\right)^{-7}=15\cdot\dfrac{3^7}{2^7}=15\cdot\dfrac{2187}{128}=\dfrac{32805}{128}\)
NT
2
1 tháng 10 2021
\(x+1+\dfrac{1}{3}+\dfrac{1}{9}+\dfrac{1}{27}+\dfrac{1}{81}=2\)
\(\Leftrightarrow x+\dfrac{121}{81}=2\)
hay \(x=\dfrac{41}{81}\)
16 tháng 12 2022
a: \(x=\left(-\dfrac{2}{3}\right)^5:\left(-\dfrac{2}{3}\right)^2=\left(-\dfrac{2}{3}\right)^3=-\dfrac{8}{27}\)
b: =>x-1/2=1/3
=>x=5/6
c: =>2/3x-1=0 hoặc 3/4x+1/2=0
=>x=3/2 hoặc x=-1/2:3/4=-1/2*4/3=-4/6=-2/3
d =>4/9:x=10/3:9/4=10/3*4/9=40/27
=>x=4/9:40/27=4/9*27/40=108/360=3/10
NT
1
\(\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{3}{9}\)
\(\Leftrightarrow\dfrac{x}{27}=-\dfrac{1}{9}\)
\(\Leftrightarrow9x=-27\)
\(\Leftrightarrow x=-\dfrac{27}{9}\)
\(\Leftrightarrow x=-3\)
\(\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{1}{3}\)
\(\Leftrightarrow\dfrac{x}{27}=\dfrac{2}{9}-\dfrac{3}{9}\)
\(\Leftrightarrow\dfrac{x}{27}=-\dfrac{1}{9}\)
Suy ra :
\(9x=-27\)
\(\Rightarrow x=-3\)