Tinh 5.4^15.9^8-4.3^17.8^9/5.2^11.6^18-7.2^28.27^6
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NT
0
TV
4
5 tháng 6 2015
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-2^2.2^{27}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
HL
0
28 tháng 3 2020
=\(\frac{5\cdot2^{30}\cdot3^{18}-2^2\cdot3^{20}\cdot2^{27}}{5\cdot2^9\cdot\left(2\cdot3\right)^{19}-7\cdot2^{29}\cdot3^{18}}\)=\(\frac{5\cdot2^{30}\cdot3^{18}-3^{20}\cdot2^{29}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)=\(\frac{2^{29}\cdot3^{18}\cdot\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}\)=2
AT
0
HT
5
22 tháng 6 2018
\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)
\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)
\(=\frac{2.\left(5.2-3^2\right)}{5.3-7.2}=\frac{2.\left(5.2-3^2\right)}{15-14}=2.\left(5.2-3^2\right)\)
23 tháng 6 2018
5.415.99−4.320.895.29.619−7.229.276
=5.(22)15.(32)9−22.320.(23)95.29.(2.3)19−7.229.(33)6
=5.230.318−229.3205.228.319−7.229.318
=229.318.(5.2−32)228.318.(5.3−7.2)
=2.(5.2−32)5.3−7.2 =2.(5.2−32)15−14 =2.(5.2−32)
M
0
\(\frac{5.4^{15}.9^8-4.3^{17}.8^9}{5.2^{11}.6^{18}-7.2^{28}.27^6}\)\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^8-\left(2^2\right).3^{17}.\left(2^3\right)^9}{5.2^{11}.\left(2.3\right)^{18}-7.2^{28}.\left(3^3\right)^6}\)\(=\frac{5.2^{30}.3^{16}-2^2.3^{17}.2^{27}}{5.2^{11}.2^{18}.3^{18}-7.2^{28}.3^{18}}\)
\(=\frac{5.2^{30}.3^{16}-2^{29}.3^{17}}{5.2^{29}.3^{18}-7.2^{28}.3^{18}}=\frac{2^{28}.3^{16}.\left(5.2^2-2.3\right)}{2^{28}.3^{16}.\left(5.2.3^2-7.3^2\right)}\)
\(=\frac{5.2^2-2.3}{5.2.3^2-7.3^2}=\frac{5.4-6}{5.2.9-7.9}=\frac{20-6}{90-63}\)
\(=\frac{14}{27}\)
\(\frac{5.4^{15}.9^8-4.3^{17}.8^9}{5.2^{11}.6^{18}-7.2^{28}.27^6}=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^8-2^2.3^{17}.\left(2^3\right)^9}{5.2^{11}.\left(2.3\right)^{18}-7.2^{28}.\left(3^3\right)^6}\)\(=\frac{5.2^{30}.3^{16}-2^2.3^{17}.2^{27}}{5.2^{11}.2^{18}.3^{18}-7.2^{28}.3^{18}}=\frac{5.2^{30}.3^{16}-2^{29}.3^{17}}{5.2^{29}.3^{18}-7.2^{28}.3^{18}}\)\(=\frac{2^{29}.3^{16}.\left(5+2-3\right)}{2^{28}.3^{18}.\left(5+2\right)}\)\(=\frac{2.4}{3^2.7}=\frac{8}{63}\)