tìm x thỏa mãn x-13/87+x-27/73+x-67/33+x-73/27=4
giúp mình mình tick cho 1 cái nha
không cần đúng nhưng có lí 1tí
thanks ^_^
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Ta có :
\(\frac{x-3}{97}+\frac{x-27}{73}+\frac{x-67}{33}+\frac{x-73}{27}=4\)
\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)
\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)
Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}>0\) Nên \(x-100=0\)
\(\Leftrightarrow x=100\)
Vậy \(x=100\)
\(\Leftrightarrow\frac{x-3}{87}+\frac{x-27}{79}+\frac{x-67}{33}+\frac{x-73}{27}-4=0\)
\(\Leftrightarrow\left(\frac{x-3}{97}-1\right)+\left(\frac{x-27}{73}-1\right)+\left(\frac{x-67}{33}-1\right)+\left(\frac{x-73}{27}-1\right)=0\)
\(\Leftrightarrow\left(\frac{x-3-97}{97}\right)+\left(\frac{x-27-73}{73}\right)+\left(\frac{x-67-33}{33}\right)+\left(\frac{x-73-27}{27}\right)=0\)
\(\Leftrightarrow\frac{x-100}{97}+\frac{x-100}{73}+\frac{x-100}{33}+\frac{x-100}{27}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\right)=0\)
Vì \(\frac{1}{97}+\frac{1}{73}+\frac{1}{33}+\frac{1}{27}\ne0\)
\(\Rightarrow x-100=0\Leftrightarrow x=100\)
a) (x + 5) / 95 + (x +10)/90 + (x + 15)/85 + (x + 20)/80 = -4
<=> (x + 5)/95 + (x + 5)/90 + 5/90 + (x + 5)/85 + 10/85+ (x + 5)/80 + 15/80 = -4
<=> (x + 5)(1/95+1/90+1/85+1/80) =-4 -5/90-10/85-15/85
<=> (x + 5)(1/95+1/90+1/85+1/80)= -1-(1 + 5/90 )-(1 + 10/85) - (1 + 15/80)
<=>(x + 5)(1/95+1/90+1/85+1/80) = -1 - 95/90 - 95/85 - 95/80
<=>(x + 5)(1/95+1/90+1/85+1/80) = -95 (1/95+1/90+1/85+1/80)
<=> x + 5 = -95 => x = -100
(x-13)/87+(x-27)/73+(x-67)/33+(x-73)/27=4
=>(x-13-87)/87+(x-27-73)/73+(x-67-33)/33+(x-73-27)/27=4-1-1-1-1
=>(x-100)/87+(x-100)/73+(x-100)/33+(x-100)/27=0
=>(x-100)*(1/87+1/73+1/33+1/27)=0
=>x-100=0
=>x=100
\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)
<=>\(\dfrac{x-13}{87}-1+\dfrac{x-27}{73}-1+\dfrac{x-67}{83}-1+\dfrac{x-73}{27}-1=0\)
<=>\(\dfrac{x-100}{87}+\dfrac{x-100}{73}+\dfrac{x-100}{83}+\dfrac{x-100}{27}=0\)
<=>\(\left(x-100\right)\left(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}\right)=0\)
Do \(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}>0\)
=>x-100=0
<=>x=100
\(a,\)\(9-25=\left(7-x\right)-\left(25+7\right)\)
\(-16=\left(7-x\right)-32\)
\(7-x=-16+32\)
\(7-x=16\)
\(x=7-16=-9\)
\(b,-7624+\left(1543+7624\right)-x=25\)
\(-7624+9167-x=25\)
\(1543-x=25\)
\(x=1543-25\)
\(x=1518\)
\(c,\left(27-514\right)-\left(486-73\right)+x=7\)
\(-487-413+x=7\)
\(-900+x=7\)
\(x=7+900\)
\(x=907\)
a, \(\left(-236\right).41+236.\left(-59\right)=\left(-236\right).\left(41+59\right)=\left(-236\right).100=-23600\)
b,\(138.\left(-125\right)-\left(-138\right).25=138.\left[\left(-125\right)-\left(-25\right)\right]=138.100=13800\)
c, \(\left(-271\right).\left(-159\right)+271.\left(-59\right)=271.\left[159+\left(-59\right)\right]=217.100=27100\)
d, \(129.\left(-73\right)+\left(-129\right).27=129.\left(-73-27\right)=129.\left(-100\right)=-12900\)
e, \(256.\left(-57\right)-\left(-256\right).\left(-43\right)=256.\left(-57-43\right)=256.\left(-100\right)=-25600\)
f, \(\left(-234\right).67+234.\left(-33\right)=234.\left(-67-33\right)=234.\left(-100\right)=-23400\)
ko cần chép đề nha
a. 236x(-41)+236x(-59)
=236x[(-41)+(-59)]
=236x(-100)
=-23600
b.-138x125-(-138)x25
=(-138)x(125-25)
=(-138)x100
=-13800
c.câu này mik giải thích là khi chuyển dấu "-" của -59 sang -271 thì -- sẽ biến thành +
c. 271x159+271x(-59)
=271x(159+(-59))
=271x100
=27100
d(-129)x73+(-129)x27
=(-129)x(73+27)
=(-129)x100
=-12900
e. (-256)x57-(-256)x(-43)
=(-256)x[57-(-43)]
=-256x100
=-25600
a, 45 x 46 + 45 x 45 - 30 - 15= 45x( 46+45) -30 -15= 45 x 91 - 30 - 15= 4095 - 30 - 15= 4050
b, 891 x 29 + 29 x 8+ 29= 29 x ( 891 + 8+ 1)= 29 x 900= 26100
c, 73 x ( 84+17) + 27 x (74+27)= 73 x 101 + 27 x 101= 101 x ( 73+27)= 101 x 100= 10100
d, chịu
d, đề bài= 13 x ( 99 + 2) + 13 x 1001+ 11 x 1300= 13 x 101 + 13 x 1001+ 13 x 1100= 13 x ( 101 + 1001 + 1100) = 13 x 2202= 28626
x - 13/87 + x - 27/73 + x- 67/33 + x - 73/27 = 4
x * 4 + ( 13/87 - 27/73 - 7/33 - 73/27 ) = 4
x * 4 + ( cậu tự tính được ko ? ) = 4
x * 4 + kết quả trên = 4
Đến đây cậu tính được rồi chứ ! Hì hì ........... Tớ kinh tính toán quá ! Sory Đức Anh nha !