17x – 25): 8 + 65 = 9²
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b: \(\left(17x-25\right):8+65=9^5:9^3\)
\(\Leftrightarrow\left(17x-25\right):8=9^2-65=81-65=16\)
\(\Leftrightarrow17x-25=128\)
hay x=9
b: (17x−25):8+65=95:93(17x−25):8+65=95:93
⇔(17x−25):8=92−65=81−65=16⇔(17x−25):8=92−65=81−65=16
⇔17x−25=128⇔17x−25=128
hay x=9
( 17x - 25 ) : 8 + 65 = 9^2
( 17x - 25 ) : 8 + 65 = 81
( 17x - 25 ) : 8 = 81 - 65
( 17x - 25 ) : 8 = 16
( 17x - 25 ) = 16 x 8
( 17x - 25 ) = 128
17x = 128 + 25
17x = 153
x = 153 : 17
x = 9
\(\left(17x-25\right):8+65=9^2\)
\(\Leftrightarrow\left(17x-25\right):8=81-65\)
\(\Leftrightarrow\left(17x-25\right):8=16\)
\(\Leftrightarrow17x-25=16.8\Leftrightarrow17x=128+25\Leftrightarrow17x=153\Leftrightarrow x=153:17=9\)
(k cho mình với nhá!)
(17x-25):8+65=92
(17x-25):8 =92-65
(17x-25):8 =27
(17x-25) =\(27\times8\)
(17x-25) =216
17x =216+25
17x =241
x =241:7
x =\(\frac{241}{17}\)
T mk nhé bạn ^...^ ^_^
(17x-25):8+65=92
(17x-25):8=92-65
(17x-25):8=27
(17x-25)=27.8
17x-25=216
17x=216+25
17x=241
x=241:17
x=
\(\left(17x-25\right):8+65=9^2\)
=> \(\frac{17x}{8}-\frac{25}{8}+65=81\)
=> \(\frac{17x}{8}=81-65+\frac{25}{8}\)
=> \(\frac{17x}{8}=\frac{153}{8}\)
=> \(17x=\left(153.8\right):8\)
=> \(17x=153\)
=> \(x=153:17=9\)
(17x - 25 ) : 8 + 65 = 92
(17x - 25 ) : 8 + 65 = 81
(17x - 25) : 8 = 81 - 65 = 16
17x - 25 = 16 x 8 = 128
17x = 128+25=153
x= 153:17 =9
a)
5.(12-x)-20=30
⇒60-5x-20=30
⇒-5x=30+20-60
⇒-5x=-10
⇒x=2
b)(17x - 25 ) : 8 + 65 = 92
(17x - 25 ) : 8 + 65 = 81
17x - 25 = 16 x 8 = 128
17x = 128+25=153
x= 153:17 =9
c)
x=23
Giải thích các bước giải:
3x – 10 = 2x + 13
3x-2x=13+10
x=23
d)4(2x+7)-3(3x-2)=24
4.2x+4.7-3.3x+3.2=24
8x+28-9x+6=24
8x-9x=24-28-6=-10
=>(-1)x=-10
x=-10:(-1)
x=10
a. \(5\cdot\left(12-x\right)-20=30\Leftrightarrow5\left(12-x\right)=50\)
\(\Leftrightarrow12-x=50:5=10\)
\(\Leftrightarrow x=12-10=2\)
b. \(\left(17x-25\right):8+65=9^2\)
\(\Leftrightarrow\left(17x-25\right):8=81-65=16\)
\(\Leftrightarrow17x-25=16:8=2\)
\(\Leftrightarrow17x=2+25=27\Leftrightarrow x=\frac{27}{17}\)
c. \(3x-10=2x+13\)
\(\Leftrightarrow3x-2x=10+13\)
\(\Leftrightarrow x=23\)
d. \(4\cdot\left(2x+7\right)-3\cdot\left(3x-2\right)=24\)
\(\Leftrightarrow8x+28-9x+6=24\)
\(\Leftrightarrow34-x=24\Leftrightarrow x=10\)
\(a.\left(17x-25\right)\div8+65=81\)
\(\left(17x-25\right):8=81-65\)
\(\left(17x-25\right):8=16\)
\(17x-25=16\times8\)
\(17x-25=128\)
\(17x=128+25\)
\(17x=153\)
\(x=153\div17\)
\(x=9.\)
\(b.720\div\left[41-\left(2x-5\right)\right]=8\times5\)
\(720\div\left[41-\left(2x-5\right)\right]=40\)
\(\left[41-\left(2x-5\right)\right]=720\div40\)
\(\left[41-\left(2x-5\right)\right]=18\)
\(2x-5=41-18\)
\(2x-5=23\)
\(2x=23+5\)
\(2x=28\)
\(x=28\div2\)
\(x=14.\)
\(c.231-\left(x-6\right)=1339\div13\)
\(231-\left(x-6\right)=103\)
\(x-6=231-103\)
\(x-6=128\)
\(x=128+6\)
\(x=134.\)
a) => ( 17x-25 ) : 8 = 16 => ( 17x -25 ) = 128 => 17x = 103 = >x = 103/7
`(17x -25) : 8 + 65 =9^2`
`=> (17x -25) : 8 =81 -65`
`=> (17x -25) : 8 =16`
`=>17x -25=16 xx 8`
`=>17x -25=128`
`=>17x=128 + 25`
`=>17x=153`
`=>x=153:17`
`=>x=9`