giúp tớ vssss
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
`a,b,c` lập thành CSC `=>a+c=2b`
Thay `a+c=2b` vào `a+b+c=15` có: `2b+b=15<=>b=5`
`=>a+c=2.5=10=>a=10-c`
Thay `b=5` vào `1/a+1/b+1/c=71/105` có:
`1/a+1/5+1/c=71/105`
`<=>1/a+1/c=10/21`
`<=>21a+21c=10ac` `(1)`
Thay `a=10-c` vào `(1)` có: `21(10-c)+21c=10(10-c)c`
`<=>[(c=3),(c=7):}=>[(a=7),(a=3):}`
KL: `[(a=7;b=5;c=3),(a=3;b=5;c=7):}`
24 The child smiled at the woman whom he didn't know
25 Mr. Brown who teaches us French is coming today
26 The city where I was born is very large
27 This is the house whose walls and roof are made of glass is a green house
28 This is Mrs.Jones whose son won the championship last year
29 Did you see Mr.John who has given a very interesting talk?
30 Do you know the American woman whose name is Margaret?
24. The child smiled at the woman whom he didn't know.
25. Mr. Brown who teaches us French is coming today.
26. The city where I was born is very large.
27. This is the house whose walls and roof are made of glass is a green house.
28. This is Mrs.Jones whose son won the championship last year.
29. Did you see Mr.John who has given a very interesting talk?
30. Do you know the American woman whose name is Margaret?
\(\dfrac{2x}{3}=\dfrac{3y}{4}=\dfrac{z}{5}=\dfrac{6x}{9}=\dfrac{6y}{8}=\dfrac{6z}{30}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\dfrac{6x}{9}=\dfrac{6y}{8}=\dfrac{6z}{30}=\dfrac{6\left(x+y+z\right)}{9+8+30}=\dfrac{6.20}{47}=\dfrac{120}{47}\\ \Rightarrow x=\dfrac{120}{47}.3:2=\dfrac{180}{47}\\ \Rightarrow y=\dfrac{120}{47}.4:3=\dfrac{160}{47}\\ \Rightarrow z=\dfrac{120}{47}.5=\dfrac{600}{47}\)
Bạn xem xem cách này có đúng không nha!
39. It is raining so we can't go to the beach.
40. If they liked this house, they would buy it.
41. Hurry up or we will be late.
42. They take pride of their school uniform.
43. Why don't we go out for a walk?
Câu 1:
BC vuông góc SA
BC vuông góc BA
=>BC vuông góc (SAB)
=>BC vuông góc SB
=>ΔSBC vuông tại B
CD vuông góc SA
DC vuông góc AD
=>DC vuông góc (SAD)
=>DC vuông góc SD
=>ΔDCS vuông tại D
Câu 2:
CD vuông góc (SAD)
AH vuông góc (SAD)
=>CD vuông góc AH
mà AH vuông góc SD
nên AH vuông góc (SCD)
=>AH vuông góc SC