2.[(7–33:33):22+99]–100
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11+22=33
22+33=55
33+44=77
44+55=99
55+66=121
66+77=143
77+88=165
88+99=187
99+100=199
11+22=33
22+33=55
33+44=77
44+55=99
55+66=121
66+77=143
77+88=165
88+99=187
99+100=199
chúc bn hok tốt
tk+kb vs mk nha m.n!
c.ơn m.n nhìu!
\(100-99+88-77+66-55+44-33+22-11\\ =\left(100-99\right)+\left(88-77\right)+\left(66-55\right)+\left(44-33\right)+\left(22-11\right)\\ =1+11+11+11+11\\ =1+11\times4\\ =1+44\\ =45\)
a 80-7 < y - 19 <63 +12 26 + 26 > 100 -y >93-59
52 > 100-y >34
y = 65,64,63,62,61,60,59,58,57,56,55,54,53,52,51,50,49,
73 < y -19< 75
y =95
\(=2.\left[\left(7-1\right):22+99\right]-100\\ =2.\left(6:22+99\right)-100\\ =2.\left(\dfrac{3}{11}+99\right)-100\\ =2.\left(\dfrac{3}{11}+\dfrac{1089}{11}\right)-100\\ =2.\dfrac{1092}{11}-100\\ =\dfrac{2184}{11}-100\\ =\dfrac{1084}{11}\)
\(2.\left[\left(7-33:33\right):22+99\right]-100\)
\(=2.\left[\left(7-1\right):22+99\right]-100\)
\(=2.\left(6:22+99\right)-100\)
\(=2.\left(\dfrac{3}{11}+99\right)-100\)
\(=2.\dfrac{1092}{11}-100\)
\(=\dfrac{2184}{11}-100\)
\(=\dfrac{1084}{11}\)