126:3+231:3+543:3
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126 : 3 + 231 : 3 + 543 : 3
= ( 126 + 231 + 543 ) : 3
= 900 : 3
= 300
126 : 3 + 231 : 3 + 543 : 3
= \(126.\frac{1}{3}+231.\frac{1}{3}+543.\frac{1}{3}\)
=\(\frac{1}{3}\left(126+231+543\right)=\frac{1}{3}.900=300\)
Câu này nghĩa là gì vậy bạn
Có phải là lấy 49 nhân cho 100 rồi chia 37 hay là biểu thức \(\frac{54\times50+49\times100}{37\times38+126\times19}\)vậy
TL
= (39 (3 -1)) : 29 : 310 = 2 : 29 x 1/3 = 1/28 x 1/3
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=> 201,ab : 126 = 1ab 126 x 1ab = 20 100 + ab 126 x ab = 7500 + ab
125 x ab = 7500 ab
= 7500 : 125 ab = 60
Vậy a = 6 ; b = 0.
3I = 31 + 32 + 33 + 34 + ... + 3101
3I - I = (31 + 32 + 33 + 34 + ... + 3101) - (30 + 31 + 32 + 33 + ... + 3100)
2I = 3101 - 30
2I = 3101 - 1
\(I=\frac{3^{101}-1}{2}\)
Gọi số thứ nhất, hai , ba theo thứ tự đề bài là a, b và c.
Theo đề bài, ta có (a+b+c):3 = 126 ; a - b = 15 suy ra a = b+15 ; b - c =9 suy ra c = b - 9
Do đó \(\frac{a+b+c}{3}=126\Rightarrow b+15+b+b-9=378\Rightarrow3b=372\Rightarrow b=124\Rightarrow c=124-9=115\)
Vậy số thứ ba là 115
= 300 em nhá cho chị xin like
126:3+ 231:3+ 543:3
= 42 + 77 + 181
= 119 + 181
= 300