(1/9)^3.(21/7)^4.(-16/5)^2
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`Answer:`
\(-\frac{7}{8}:\frac{21}{16}-\frac{5}{3}.\left(\frac{1}{5}-\frac{7}{10}\right)\)
\(=-\frac{7}{8}.\frac{16}{21}-\frac{5}{3}.\left(-\frac{1}{2}\right)\)
\(=-\frac{2}{3}-\left(-\frac{5}{6}\right)\)
\(=\frac{1}{6}\)
\(\frac{1}{5}.\left(\frac{1}{2}-\frac{1}{3}\right):\left(-\frac{9}{10}\right)+\left(-\frac{7}{3}\right)\)
\(=\frac{1}{5}.\frac{1}{6}.\left(-\frac{10}{9}\right)-\frac{7}{3}\)
\(=\frac{1}{30}.\left(-\frac{10}{9}\right)-\frac{7}{3}\)
\(=-\frac{1}{27}-\frac{7}{3}\)
\(=-\frac{64}{27}\)
1. -x+20 = -(-15)-8+13
=> -x=15-8+13-20
=> -x=0
=> x=0
2. -(-10)+x=-13+(-9)+(-6)
=> 10+x=-13-9-6
=> x = -13-9-6-10
=> x = -38
3. 8-(-12)+10=-(-14)-x
=> 8+12+10=14-x
=> x = 14-8-12-10
=> x = -16
4. -(+12)+(-x)-(-3)=5-(-7)
=> -12-x+3=5+7
=> -x=5+7+12-3
=> -x=21
=> x=-21
5. 14-x+(-10)=-(-9)+(+15)
=> 14-x-10=9+15
=> -x=9+15-14+10
=> -x=20
=> x=-20
6. 12-(-17)+(-3)=-5+x
=> 12+17-3+5=x
=> x=31
7. x-(-19)-(+32)=14-(+16)
=> x+19-32=14-16
=> x=14-16+32-19
=> x=11
8. x-|-15|-|7|=-(-9)+|-5|
=> x-15-7=9+5
=> x=9+5+7+15
=> x=36
9. 15-x+17=13-(-21)
=> 15-x+17=13+21
=> -x=13+21-15-17
=> -x=2
=> x=-2
10. -|-5|-(-x)+4=3-(-25)
=> -5+x+4=3+25
=> x=3+25-4+5
=> x=29
1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)
\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)
\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)
\(=\dfrac{40+\left(-135\right)+30}{180}\)
\(=\dfrac{-65}{180}\)
\(=\dfrac{-13}{36}\)
2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)
\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)
\(=\dfrac{-21}{36}-\dfrac{22}{36}\)
\(=\dfrac{-21-22}{36}\)
\(=\dfrac{-43}{36}\)
3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)
\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)
\(=\dfrac{14}{16}-\dfrac{-5}{16}\)
\(=\dfrac{14-\left(-5\right)}{16}\)
\(=\dfrac{19}{16}\)
4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)
\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)
\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)
\(=\dfrac{30-\left(-72\right)-25}{80}\)
\(=\dfrac{77}{80}\)
\(\left(\dfrac{1}{9}\right)^3.\)\(\left(\dfrac{21}{7}\right)^4\).\(\left(\dfrac{-16}{5}\right)^2\)
= \(\dfrac{1}{729}\) . \(81\) . \(\dfrac{256}{25}\)
= \(\dfrac{1}{9}.\dfrac{256}{25}\) = \(\dfrac{256}{225}\)