53 - 145 - 359 - 53 + 145 + 259
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a: Ta có: \(-5+\left(-37\right)-45+151-37+151\)
\(=\left(-5-45\right)-\left(37+37\right)+2\cdot151\)
\(=-50-74+302\)
=178
b: Ta có: \(53-145-359-53+145-259\)
\(=\left(53-53\right)-\left(145-145\right)-\left(359+259\right)\)
\(=-618\)
\(a.\left(35-815\right)-\left(795-65\right)\\ =35-815-795+65\\ =\left(35+65\right)-\left(815+795\right)\\ =100-1610=-1510\)
Bài 2:
a: Ta có: \(\left(35-815\right)-\left(795-65\right)\)
\(=35-815-795+65\)
\(=100-1600\)
=-1500
b: Ta có: \(5-197-2015-2015\)
\(=-2010-2212\)
=-4222
c: Ta có: \(1259-1409-12+1259+1409\)
\(=2518-12\)
=2506
(145 x 99 + 145 ) - ( 143 x 102 – 143 × 2 ) + 54 x 47 - 47 x 53 - 20 - 27
= 145 × (99 + 1) – 143 × (102 – 2) + 47 × (54 – 53) – (20 + 27)
= 145 × 100 – 143 × 100 + 47 × 1 – 47
= 100 × (145 – 143) + (47 – 47)
= 100 × 2 + 0
= 200
(145 x 99 + 145 ) - ( 143 x 102 – 143 × 2 ) + 54 x 47 - 47 x 53 - 20 - 27
= 145 × (99 + 1) – 143 × (102 – 2) + 47 × (54 – 53) – (20 + 27)
= 145 × 100 – 143 × 100 + 47 × 1 – 47
= 100 × (145 – 143) + (47 – 47)
= 100 × 2 + 0
= 200
(145 x 99 + 145 ) - ( 143 x 102 – 143 × 2 ) + 54 x 47 - 47 x 53 - 20 - 27
= 145 × (99 + 1) – 143 × (102 – 2) + 47 × (54 – 53) – (20 + 27)
= 145 × 100 – 143 × 100 + 47 × 1 – 47
= 100 × (145 – 143) + (47 – 47)
= 100 × 2 + 0
= 200
= 145 x (99+1) - 143 x ( 102-2) + 47 x ( 54 - 53) -20-27
= 145 x 100 - 143 x 100 + 47 x 1 -20-27
= 100 x ( 145 - 143 ) + 47 - 20 - 27
= 200 + 47 - 20 - 27
= 200
c, 126 - (126 - 33)=126-126+33=33
d, (-53 - 23) - (567 - 53) =-76-567+53=-590
e, 145 - (23 - 45) - (-23 - 10) =145+22+33=200
145,8 x 4 - 53,85 + 5 x 145,8 - 46,15 + 145,8
= 145,8 x (4 + 5 + 1) - (53,85 + 46,15)
= 145,8 x 10 - 100
= 1458 - 100
= 1358
53 - 145 - 359 - 53 + 145 + 259
=( 53 - 53 ) + ( 145 - 145) - ( 359 - 259)
= 0 + 0 - 100
= -100