1/15+1/35+1/63+1/99+......+1/255=?
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A=1/15+1/35+1/63+1/99+1/143+1/195+1/255+1/323
=> A = 1/3.5 + 1/5.7 + 1/7.9 + 1/9.11 + 1/11.13 + 1/13.15 + 1/15.17 + 1/17.19
=> 2A = 1/3 - 1/5 + 1/5 - 1/7 + ..... + 1/17 - 1/19
=> 2A = 1/3 - 1/19
=> 2A = 16/57 => A = 16/57 : 2 = 8/57
=>=> A = 1/3.5 + 1/5.7 + 1/7.9 + 1/9.11 + 1/11.13 + 1/13.15 + 1/15.17 + 1/17.19
=>=> 2A = 1/3 - 1/5 + 1/5 - 1/7 + ..... + 1/17 - 1/19
=> 2A = 1/3 - 1/19
=> 2A = 16/57 => A = 16/57 : 2 = 8/57
= 1/(3x5) + 1/(5x7) + 1/(7x9) +.....+ 1/(99x101) =( 1/3 -1/5 + 1/5 -1/7 +1/7 - 1/9 +....+ 1/99 -1/101 ) :2 = (1/3 -1/101) : 2 = 98/303 : 2 = 49/303
=1/3*5+1/5*7+1/7*9+...+1/99*101
=1/3-1/5+1/5-1/7+...+1/99-1/101
=1/3-1/101
=98/303
Đặt \(B=\frac{3}{15}+\frac{3}{35}+\frac{3}{63}+\frac{3}{99}+\frac{3}{143}\)
\(\Leftrightarrow B=\frac{3}{3.5}+\frac{3}{5.7}+\frac{3}{7.9}+\frac{3}{9.11}+\frac{3}{11.13}\)
\(\Leftrightarrow2B=3\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)
\(\Leftrightarrow2B=3\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)
\(\Leftrightarrow2B=3\left(\frac{1}{3}-\frac{1}{13}\right)=1-\frac{3}{13}=\frac{10}{13}\)
\(\Leftrightarrow A=1+\frac{3}{15}+\frac{3}{35}+\frac{3}{63}+\frac{3}{99}+\frac{3}{143}=1+\frac{10}{13}=\frac{23}{13}\)
1/3 + 1/15 + 1/35 + 1/63 + 1/99 + 9999
= 1/3 + ( 1/5 + 1/35 + 1/63 ) + 1/99 = 9999
= 1/3 + 1111/9999 + 1/99
= 3333/9999 + 1111/9999 +101/9999
= 4545/9999
\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}\)
\(=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\)
\(=1-\frac{1}{11}\)
\(=\frac{10}{11}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
\(=1-\frac{1}{7}\)
\(=\frac{6}{7}\)
\(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}\)
\(=\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\)
\(=1-\frac{1}{11}\)
\(=\frac{10}{11}\)
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
\(=1-\frac{1}{7}\)
\(=\frac{6}{7}\)
A = 1/15 + 1/35 + 1/63 + 1/99 + ....... + 1/9999
A = 1/3 x 5 + 1/5 x 7 + 1/9 x7 + .........+ 1/99 x101
A = 1/2 x ( 1/3 -1/5 + 1/5 - 1/7 + 1/7 - 1/9 + ...... + 1/99 - 1/101
A = 1/2 x ( 1/3 - 1/99 )
A = 1/2 x 98/303
A = 49/303
A = 1/3.5 +1/5.7 + 1/7.9 + 1/9.11 + ... + 1/99. 101
= 1/2.(2/3.5+ 2/5.7 + 2/7.9 + ...+2/99.101)
= 1/2.(1/3 - 1/5 - 1/5 - 1/7 - 1/7 - 1/9 + .... +1/99 - 1/101
=1/2.(1/3 - 1/101)
=1/2 .98//303
=49/303
Dấu . là nhân đó nha bạn
A = 1/15 + 1/35 + 1/63 + 1/99 + ... + 1/255
A = 1/3x5 + 1/5x7 + 1/7x9 + 1/9x11 +...+ 1/15x17
2A = 2/3x5 + 2/5x7 + 2/7x9 + .... + 1/15x17
2A = 1/3 - 1/5 + 1/5 - 1/7 + 1/7 - 1/9 + .... + 1/15 - 1/17
2A = 1/3 - 1/17 = 14/51
A = 14/51 : 2 = 7/51
ta tách biểu thức trên thành 1/ 3*5+1/ 5*7+1/ 7*9+1/ 9*11+...+1/ 15*17
từ biểu thúc trên có:
1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+...+1/15-1/17
rút gọn còn 1/3-1/17
còn lại bạn tự tính nha