1/5 . (-5/5 - 10 ) + 5x = x-2/3
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a)
<=> 10x - 35 + 16x - 10 = 5
<=> 10x + 16x = 5 + 35 + 10
<=> 26x = 50
<=> x = 50/26 = 25/13
\(A.3x-\frac{3}{2}-5x+\frac{10}{3}=1\)
\(3x-\frac{3}{2}-5x=-\frac{7}{3}\)
\(3x-5x=-\frac{7}{3}+\frac{3}{2}\)
\(-2x=-\frac{5}{6}\)
\(x=-\frac{5}{6}:\left(-2\right)\)
\(x=\frac{5}{12}\)
a)
\(\left(1-\dfrac{1}{5}\right)x\left(1-\dfrac{2}{5}\right)x...x\left(1-\dfrac{9}{5}\right)\\ =\left(1-\dfrac{1}{5}\right)x...x\left(1-\dfrac{5}{5}\right)x...x\left(1-\dfrac{9}{5}\right)\\ =\left(1-\dfrac{1}{5}\right)x...x0x...x\left(1-\dfrac{9}{5}\right)=0\)
x là nhân nhé :))
b)
\(\dfrac{1}{2}x\dfrac{2}{3}x...x\dfrac{9}{10}\\ =\dfrac{1x2x...x9}{2x3x...x10}=\dfrac{2x3x...x9}{2x3x...x9x10}=\dfrac{1}{10}\)
\(a,80-\left(10x-5\right)=45\\ \Rightarrow80-10x+5=45\\ \Rightarrow-10x=-40\\ \Rightarrow x=4\)
\(b,\left(x+1\right)\left(x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
\(c,\left|5+5x\right|=2^2.5\\ \Rightarrow\left|5+5x\right|=20\\ \Rightarrow\left[{}\begin{matrix}5+5x=20\\5+5x=-20\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x=15\\5x=-25\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)
\(d,-10-\left(-5\right)+\left(3-x\right)=-8\\ \Rightarrow-10+5+3-x=-8\\ \Rightarrow-x=-6\\ \Rightarrow x=6\)
a) 80-(10x-5)=45
=> 80 - 10 x + 5 =45
=>-10x = -40
=>x=4
b)(x+1)×(x-2)=0
\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x=2+0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
c) |5+5x|=2^2×5
=>|5+5x|=20
\(\Rightarrow\left[{}\begin{matrix}5+5x=-20\\5+5x=20\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-5\\x=3\end{matrix}\right.\)
d) -10-(-5)+(3-x)=-8
=>-10+5 +3-x=-8
=>2+x=8
=>x=6
`1/5.(-5/5-10)+5x=x-2/3`
`1/5.(-1-10)+5x-x=-2/3`
`1/5 .(-11)+4x=-2/3`
`4x=-2/3+11/5=23/15`
`x=23/15:4=23/60`