Tìm x biết (x-10)/30 + (x-14)/43 + (x-5) +(x-148)/8=0
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NT
1
YN
7 tháng 1 2022
Answer:
Có:
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
\(\Rightarrow\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x+100}{8}-6=0\)
\(\Rightarrow\left(\frac{x-10}{30}-3\right)+\left(\frac{x-14}{43}-2\right)+\left(\frac{x-5}{95}-1\right)+\frac{x-100}{8}=0\)
\(\Rightarrow\frac{x-100}{30}+\frac{x-100}{43}+\frac{x-100}{95}+\frac{x-100}{8}=0\)
\(\Rightarrow\left(x-100\right)\left(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{9}\right)=0\)
Mà \(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\ne0\Leftrightarrow\left(x-100\right)\left(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\right)=0\)
\(\Leftrightarrow x-100=0\Leftrightarrow x=100\)
NN
0
NV
0
CR
1
8 tháng 5 2021
\(\left(\frac{x-10}{30}-3\right)+\left(\frac{x-14}{43}-2\right)+\left(\frac{x-5}{95}-1\right)+\left(\frac{x-148}{8}+6\right)=0\)
\(\Leftrightarrow\left(\frac{x-10}{30}-\frac{90}{30}\right)+\left(\frac{x-14}{43}-\frac{86}{43}\right)+\left(\frac{x-5}{95}-\frac{95}{95}\right)+\left(\frac{x-148}{8}+\frac{48}{8}\right)=0\)
\(\Leftrightarrow\frac{x-100}{30}+\frac{x-100}{43}+\frac{x-100}{95}+\frac{x-100}{8}=0\)
\(\Leftrightarrow\left(x-100\right).\left(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\right)=0\)
\(\Rightarrow x-100=0\)( Do \(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\ne0\)
=> x=100
14 tháng 7 2016
ta co( x-10 / 30 ) -3 + ( x -14 / 43 ) -2 + ( x-5 / 95 ) -1 + ( x- 148 / 8) + 6 =0
=> (x- 10 -90 / 30 ) + ( x- 14-86 / 43 ) + ( x- 5- 95 / 95) + ( x- 148 +48 ) =0
=> x-100 /30 + x-100 / 43 + x- 100 / 95 + x- 100 / 8 = 0
=> x-100 .( 1/30 + 1/43 +1/ 95 +1/ 8) =0
ma 1/30 + 1/43 + 1/ 95 + 1/8 khac 0 => x-100 =0 => x=100
23 tháng 2 2018
a, => (x-10/30 - 3) + (x-14/43 - 2) + (x-5/95 - 1) + x-100/8 = 0 ( vì x-148/8 = x-100/8 + 48/8 = x-100/8 + 6 )
=> x-100/30 + x-100/43 + x-100/95 + x-100/8 = 0
=> (x-100).(1/30 + 1/43 + 1/95 + 1/8) = 0
=> x-100 = 0 ( vì 1/30+1/43+1/95+1/8 > 0 )
=> x = 100
Vậy x = 100
Tk mk nha
KG
0
HN
3
NV
27 tháng 7 2016
\(\frac{x-10}{30}+\frac{x-14}{43}+\frac{x-5}{95}+\frac{x-148}{8}=0\)
\(\Rightarrow\frac{x-10}{30}-3+\frac{x-14}{43}-2+\frac{x-5}{95}-1+\frac{x-148}{8}+6=0\)
\(\Rightarrow\frac{x-100}{30}+\frac{x-100}{43}+\frac{x-100}{95}+\frac{x-100}{8}=0\)
\(\Rightarrow\left(x-100\right)\left(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\right)=0\)
mà \(\frac{1}{30}+\frac{1}{43}+\frac{1}{95}+\frac{1}{8}\ne0\)
=> x - 100 = 0 => x = 100
Vậy x = 100
