\(\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{15}\right)\times\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\)
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\(\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right).\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}=\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right).\frac{12}{49}}{\frac{10}{3}+\frac{2}{9}}=\frac{\left(\frac{13}{20}-\frac{1}{5}\right).\frac{12}{49}}{\frac{32}{9}}=\frac{\frac{9}{20}.\frac{12}{49}}{\frac{32}{9}}=\frac{\frac{27}{245}}{\frac{32}{9}}=\frac{243}{7840}\)
Có đúng không vu bao quynh?
\(\frac{\left(\frac{3}{15}+\frac{1}{4}+\frac{7}{20}\right)\times\frac{17}{49}}{5\frac{1}{3}+\frac{2}{5}}=\frac{\left(\frac{1}{5}+\frac{1}{4}+\frac{7}{20}\right)\times\frac{17}{49}}{\frac{16}{3}+\frac{2}{5}}\)
=\(\frac{\left(\frac{4}{20}+\frac{5}{20}+\frac{7}{20}\right)\times\frac{17}{49}}{\frac{80}{15}+\frac{6}{15}}=\frac{\frac{16}{20}\times\frac{17}{49}}{\frac{86}{15}}=\frac{\frac{4}{5}\times\frac{17}{49}}{\frac{86}{15}}\)
=\(\frac{68}{245}\times\frac{15}{86}=\frac{102}{2107}\)
\(\frac{\left(\frac{3}{15}+\frac{1}{4}+\frac{7}{20}\right)\times\frac{17}{49}}{5\frac{1}{3}+\frac{2}{5}}\)
\(=\frac{\left(\frac{12}{60}+\frac{15}{60}+\frac{21}{60}\right)\times\frac{17}{49}}{\frac{16}{3}\times\frac{2}{5}}\)
\(=\frac{\frac{48}{60}\times\frac{17}{49}}{\frac{80}{15}+\frac{6}{15}}\)
\(=\frac{\frac{816}{2940}}{\frac{86}{15}}\)
\(=\frac{816}{2940}:\frac{86}{15}\)
\(=\frac{816}{2940}\times\frac{15}{86}\)
\(=\frac{68}{245}\times\frac{15}{86}\)
\(=\frac{102}{2107}\)
đề bài là:(3/20+1/2-1/5)-12/49 phần 10/3 dổi từ3mot phan ba +2/9 đúng ko
\(\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right)-\frac{12}{49}=\left(\frac{3}{20}+\frac{10}{20}-\frac{4}{20}\right)-\frac{12}{49}=\frac{9}{20}-\frac{12}{49}=\frac{201}{980}\)
\(3\frac{1}{3}+\frac{2}{9}=\frac{10}{3}+\frac{2}{9}=\frac{30}{9}+\frac{2}{9}=\frac{32}{9}\)
tick đúng cho mk nha tran Thi Thanh Hong 01
Ta có nếu theo quy luật như trên thì sẽ có 1 thừa số là\(\frac{1}{49}-\frac{1}{7^2}\)
Mà chúng bằng 0 nên tích trên bằng 0
\(=\frac{16}{5}.\frac{15}{16}-\left(\frac{3}{4}+\frac{2}{7}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{21}{28}+\frac{8}{28}\right):\left(\frac{-29}{28}\right)\)
\(=3-\left(\frac{29}{28}\right).\left(\frac{-28}{29}\right)\)
\(=3-\left(-1\right)\)
\(=4\)
b) \(=\left(\frac{1}{4}+\frac{25}{2}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3}{8}-\frac{1}{12}\right)\right)\)
\(=\left(\frac{4}{16}+\frac{200}{16}-\frac{5}{16}\right):\left(12-\frac{7}{12}:\left(\frac{3.3}{2.3.4}-\frac{2}{2.3.4}\right)\right)\)
\(=\left(\frac{199}{16}\right):\left(12-\frac{7}{12}:\left(\frac{9}{24}-\frac{2}{24}\right)\right)\)
\(=\frac{199}{16}:\left(12-\frac{7}{12}.\frac{24}{7}\right)\)
\(=\frac{199}{16}:\left(12-2\right)\)
\(=\frac{199}{16}:10\)
\(=\frac{199}{160}\)
c) \(\left(\frac{-3}{5}+\frac{5}{11}\right):\frac{-3}{7}+\left(\frac{-2}{5}+\frac{6}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-33}{55}+\frac{25}{55}\right):\frac{-3}{7}+\left(\frac{4}{5}\right):\frac{-3}{7}\)
\(\left(\frac{-8}{55}\right).\frac{-7}{3}+\frac{4}{5}.\frac{-7}{3}\)
\(\frac{-7}{3}\left(\frac{-8}{55}+\frac{4}{5}\right)\)
\(\frac{-7}{3}.\frac{36}{55}=\frac{-84}{55}\)