Tính :1 + 3 + 5 + 7 + ... + (2n - 1) = 225 Giải :Theo công thức tính dãy số , ta có :\(\frac{\left\{\left[\left(2n-1\right)-1\right]:2+1\right\}.\left[\left(2n-1\right)+1\right]}{2}=225\)\(\frac{\left\{\left[2n-2\right]:2+1\right\}.2n}{2}=225\)\(\left\{\left[2n-2\right]:2+1\right\}.n=450\)(Lượt giản thừa số 2)\(\left\{\frac{2n-2}{2}+1\right\}.n=225\)\(\left\{\frac{2n-2}{2}+\frac{2}{2}\right\}.n=225\)\(\frac{2n-2+2}{2}.n=225\)\(\frac{2n}{2}.n=225\)\(n^2=225\)\(\Rightarrow...
Đọc tiếp
Tính :
1 + 3 + 5 + 7 + ... + (2n - 1) = 225
Giải :
Theo công thức tính dãy số , ta có :
\(\frac{\left\{\left[\left(2n-1\right)-1\right]:2+1\right\}.\left[\left(2n-1\right)+1\right]}{2}=225\)
\(\frac{\left\{\left[2n-2\right]:2+1\right\}.2n}{2}=225\)
\(\left\{\left[2n-2\right]:2+1\right\}.n=450\)(Lượt giản thừa số 2)
\(\left\{\frac{2n-2}{2}+1\right\}.n=225\)
\(\left\{\frac{2n-2}{2}+\frac{2}{2}\right\}.n=225\)
\(\frac{2n-2+2}{2}.n=225\)
\(\frac{2n}{2}.n=225\)
\(n^2=225\)
\(\Rightarrow n=\sqrt{225}=15\)
