\(\frac{2\times6^9-2^5\times18^4}{2^6\times6^8}\)
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\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)
\(=\frac{-1}{3}\)
Ta có:
\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(=\frac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}\)
\(=\frac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot\left(1+5\right)}\)
\(=-\frac{2}{6}=-\frac{1}{3}\)
=\(\frac{3\times3\times3\times5\times3\times7\times2\times6\times4\times5}{5\times2\times3\times5\times3\times3\times3\times6\times4}=7\)
\(\frac{1.2.6.4.6.4.5.2}{2.3.6.8.6.2.2.2.8.10}=\frac{1}{96}\)
\(\frac{2\cdot6^9-2^5\cdot18^4}{2^6\cdot6^8}=\frac{2^{10}\cdot3^9-2^9\cdot3^8}{2^{14}\cdot3^8}=\frac{2^9\cdot3^8}{2^{14}\cdot3^8}=\frac{1}{2^5}\)
hình như sai....